A hydrocarbon 'X' with formula ${\mathrm{C}}_6{\mathrm{H}}_8$ uses two moles of ${\mathrm{H}}_2$ on catalystic hydrogenation of its one mole. On ozonolysis, 'X' yields two moles of methane dicarbaldehyde. The hydrocarbon 'X' is :

But-$2$-yne is reacted separately with one mole of Hydrogen as shown below:

$\underset{¯}{\mathrm{B}}\underset{\mathrm{liq} {\mathrm{NH}}_3}{\overset{\mathrm{Na}}{\leftarrow }}{\mathrm{CH}}_3-\underset{+{\mathrm{H}}_2}{\mathrm{C}\equiv }\mathrm{C}-{\mathrm{CH}}_3\underset{∆}{\overset{\mathrm{Pd}/\mathrm{C}}{\to }}\underset{¯}{\mathrm{A}}$

Identify the incorrect statements from the options given below:

A. A is more soluble than $\mathrm{B}$.
B. The boiling point & melting point of $\mathrm{A}$are higher and lower than $\mathrm{B}$ respectively.

C. A is more polar than $\mathrm{B}$ because dipole moment of $\mathrm{A}$ is zero.
D. ${\mathrm{Br}}_2$ adds easily to $\mathrm{B}$ than $\mathrm{A}$.