A network of four capacitors of capacity equal to $C_1=C, C_2=2C, C_3=3C \text{and} C_4=4C$ are connected to a battery as shown in the figure. The ratio of the charges on $C_2$ and $C_4$ is :—

A 10 volts battery is connected to three capacitors; $C_1=2 \mathrm{\mu F}, C_2=3 \mathrm{\mu F} \text{and} C_3=5 \mathrm{\mu F},$ as shown. The charges on the capacitors $C_1, C_2 \text{and} C_3$ are respectively :

Two materials of dielectric constants $k_1 \text{and} k_2$ are introduced to fill the space between the two parallel plates of a capacitor as shown in figure. The capacity of the capacitor is :

Two capacitors, $3 \mathrm{\mu F}$ and $4 \mathrm{\mu F}$, are individually charged across a $6 \mathrm{V}$ battery. After being disconnected from the battery, they are connected together with the negative plate of one connected to the positive plate of the other. What is the final total energy stored ?

In an isolated parallel plate capacitor of capacitance $C$, the four surfaces have charges $Q_1, Q_2, Q_3 \text{and} Q_4$ as shown. The potential difference between the plates is :

Assertion: Increasing the charge on the plates of a capacitor means increasing the capacitance.

Reason: Because $Q=CV\Rightarrow Q\infty C$

Assertion: The capacitance of a capacitor depends on the shape, size and geometrical placing of the conductors and its medium between them.

Reason: When a charge $q$ passes through a battery of emf $E$ from the negative terminal to an positive terminal, an amount $qE$ of work is done by the battery.