A police jeep is chasing a culprit going on a motorbike. The motorbike crosses a turn at a speed of $72 \mathrm{km} {\mathrm{h}}^{-1}$. The jeep follows it at a speed of $108 \mathrm{km} {\mathrm{h}}^{-1}$, crossing the turn $10$ $\mathrm{s}$ later than the bike (keeping constant speed). After crossing the turn, the jeep accelerates with constant acceleration $2 \mathrm{m} {\mathrm{s}}^{-2}$. Assuming bike travels at a constant speed, after travelling a distance $20\alpha \mathrm{m}$ from the turn, the jeep catches the bike where $\alpha$ is an integer. Find $\alpha$.

The acceleration time plot for a particle (starting from rest) moving on a straight line is shown in the figure. For given time interval,

A particle moves along the $Y$ -axis and its $y$ -coordinate $\left(y\right)$changes with time $\left(t\right)$ as $y=u(t-2)+a(t-2{)}^2$.

The graph below gives the coordinator of a particle travelling along the $X-$axis as a function of $\tan \theta$. $AM$ is the tangent to the curve at the starting moment and $BN$ is tangent at the end moment $\left({\theta }_1={\theta }_2=120°\right)$

The direction $(i$ or $-i)$ of acceleration during the first $10$ seconds is