A rational number between $\sqrt{2}$ and $\sqrt{3}$ is

Important Questions on Number Systems

MEDIUM

9th CBSE

IMPORTANT

NCERT Exemplar Mathematics - Class 9>Chapter 1 - Number Systems>Exercise>Q 9

The value of $1.999\dots$ in the form $\frac{\mathrm{p}}{\mathrm{q}},$ where $\mathrm{p}$and$\mathrm{q}$ are integers and $\mathrm{q}\ne 0$, is

EASY

9th CBSE

IMPORTANT

NCERT Exemplar Mathematics - Class 9>Chapter 1 - Number Systems>Exercise>Q 10

$2\sqrt{3}+\sqrt{3}$ is equal to

EASY

9th CBSE

IMPORTANT

NCERT Exemplar Mathematics - Class 9>Chapter 1 - Number Systems>Exercise>Q 11

$\sqrt{10}\times \sqrt{15}$ is equal to

EASY

9th CBSE

IMPORTANT

NCERT Exemplar Mathematics - Class 9>Chapter 1 - Number Systems>Exercise>Q 12

The number obtained on rationalising the denominator of $\frac{1}{\sqrt{7}-2}$ is

MEDIUM

9th CBSE

IMPORTANT

NCERT Exemplar Mathematics - Class 9>Chapter 1 - Number Systems>Exercise>Q 13

$\frac{1}{\sqrt{9}-\sqrt{8}}$ is equal to 

MEDIUM

9th CBSE

IMPORTANT

NCERT Exemplar Mathematics - Class 9>Chapter 1 - Number Systems>Exercise>Q 14

After rationalising the denominator of $\frac{7}{3\sqrt{3}-2\sqrt{2}},$ we get the denominator as

EASY

9th CBSE

IMPORTANT

NCERT Exemplar Mathematics - Class 9>Chapter 1 - Number Systems>Exercise>Q 15

The value of $\frac{\sqrt{32}+\sqrt{48}}{\sqrt{8}+\sqrt{12}}$ is equal to

MEDIUM

9th CBSE

IMPORTANT

NCERT Exemplar Mathematics - Class 9>Chapter 1 - Number Systems>Exercise>Q 16

If $\sqrt{2}=1.4142$, then $\sqrt{\frac{\sqrt{2}-1}{\sqrt{2}+1}}$ is equal to