A solution contains $\left[\mathrm{NaCl}\right]=\left[{\mathrm{Na}}_2{\mathrm{CO}}_3\right]=\mathrm{C} \mathrm{M}$. Upon gradually adding ${\mathrm{AgNO}}_3$$\left(\mathrm{s}\right):$(Assume no hydrolysis of any ion.)

Consider the coordination compound, [Co(NH₃)₆]Cl₃. In the formation of this complex, the species which acts as the Lewis acid is :

The following equilibrium exists in a saturated solution of ${\mathrm{NH}}_4\mathrm{Cl}.$

 ${\mathrm{NH}}_4{\mathrm{Cl}}_{\left(\mathrm{S}\right)}\rightleftharpoons {\mathrm{NH}}_4^{+}\left(\mathrm{aq}\right)+{\mathrm{Cl}}_{\left(\mathrm{aq}\right)}$ ${\mathrm{\Delta H}}_{25°\mathrm{C}}=3.5 \mathrm{kcal} {\mathrm{mol}}^{-1}$
A change that will shift the equilibrium to the right is

A solution of ${\mathrm{Na}}_2{\mathrm{CO}}_3$ is added drop by drop to one litre of a solution containing ${10}^{-4} \mathrm{mole}$ of ${\mathrm{Ba}}^{2+}$ and ${10}^{-5}$ $\mathrm{mole}$of ${\mathrm{Ag}}^{+}.$ If ${\mathrm{K}}_{\mathrm{sp}}$ for ${\mathrm{BaCO}}_3$ is $8.1\times {10}^{-9}$ and ${\mathrm{K}}_{\mathrm{sp}}$ for ${\mathrm{Ag}}_2{\mathrm{CO}}_3$ is $6.9\times {10}^{-12}$, then which is not true?
Assume no hydrolysis of ${\mathrm{CO}}_3^{2-}$ ion.