
A straight wire of length metre is carrying a current of and the magnetic field due to it is measured at a point distant from it. If the wire is to be bent into a circle and is to carry the same current as before, the ratio of the magnetic field at its centre to that obtained in the first case would be




Important Questions on Magnetic Effect of Electric Current
The magnetic field at the centre of coil of turns, bent in the form of a square of side carrying current , is,

Two identical wires and , each of length carry the same current . Wire A bent into a circle of radius and wire is bent to form a square of the side . If and are the values of the magnetic field at the centers of the circle and square respectively, then the ratio is

A length of wire carrying current is to be bent into a circle or a square, each of one turn. The ratio of (greater) to (smaller) is nearly,

A current-carrying thin uniform wire of length is bent like a square so that it produces a magnetic induction at the centre of the square. When the same wire is bent like a circle, it produces a magnetic induction at the centre of the circle. The ratio between and is,

A long conducting wire carrying a current is bent at (see figure). The magnetic field at a point on the right bisector of bending angle at a distance from the bend is is the permeability of free space)

Current is flowing in a conductor shaped as shown in the figure. The radius of the curved part is and the length of straight portion is very large. The value of the magnetic field at the centre will be

The magnetic induction at the centre $O$ in the figure shown is

Two long parallel wires $P$ and $Q$ are both perpendicular to the plane of the paper with distance between them. If and carry current of and respectively in the same direction, then the magnetic field at a point half way between the wires is
