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An uncharged capacitor having capacitance C is connected across a battery of emf V. Now, the capacitor is disconnected and then, reconnected across the same battery but with reversed polarity. Which of the statement is incorrect?

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Important Questions on Capacitance

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A capacitor of capacitance C is initially charged to a potential difference of V volt. Now, it is connected to a battery of 2V with opposite polarity. The ratio of heat generated to the final energy stored in the capacitor will be
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In an isolated parallel plate capacitor of capacitance C, the four surfaces have charges Q1, Q2, Q3 and Q4 as shown. The potential difference between the plates is :

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Assertion: Increasing the charge on the plates of a capacitor means increasing the capacitance.

Reason: Because Q=CVQ C

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Assertion: The capacitance of a capacitor depends on the shape, size and geometrical placing of the conductors and its medium between them.

Reason: When a charge q passes through a battery of emf E from the negative terminal to an positive terminal, an amount qE of work is done by the battery.

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Assertion :- A dielectric slab is inserted between the plates of an isolated charged capacitor. The charge on the capacitor will remain the same.

Reason :- Charge on an isolated system is conserved.

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Assertion: Two adjacent conductors carrying the same charge can be at different potentials.

Reason: The conductors may have different sizes and hence different capacitances.

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Assertion: When charges are shared between two parallel plate capacitors, a charge of the system is conserved, but some energy is lost.

Reason: During the sharing of charges, some energy is dissipated as heat.

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Assertion:- On filling the space between the plates of a parallel plate air capacitor with a dielectric, the capacity of the capacitor is increased.

Reason:- The same amount of charge can be stored at a reduced potential.