Achieve Indian Airforce Agniveer Vayu Physics Practice Book>Chapter 12 - Thermodynamics>Exercise>Q 3

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IMPORTANT

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Assertion: In the process $V = \frac{K}{T}$ , if the volume of gas increases, then work done by gas decreases.

Reason: Work done in the above process is $d W = - n R d T$

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Important Questions on Thermodynamics

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Achieve Indian Airforce Agniveer Vayu Physics Practice Book>Chapter 12 - Thermodynamics>Exercise>Q 4

2 k g

monoatomic gas of density

8 k g / m^{3}

and pressure

4 \times 10^{3} N / m^{2},

is enclosed in a container. Internal energy of gas will be:

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Achieve Indian Airforce Agniveer Vayu Physics Practice Book>Chapter 12 - Thermodynamics>Exercise>Q 5

2 kg

of a monoatomic gas is at a pressure of

4 \times 10^{4} N m^{- 2}

. The density of the gas is

8 kg m^{- 3}

. What is the order of energy of the gas due to its thermal motion?

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Achieve Indian Airforce Agniveer Vayu Physics Practice Book>Chapter 12 - Thermodynamics>Exercise>Q 6

In the figure, a certain mass of gas traces three paths

1, 2, 3

from state

A

to state

B

. If work done by the gas along three paths are

W_{1}, W_{2}, W_{3}

respectively, then
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Achieve Indian Airforce Agniveer Vayu Physics Practice Book>Chapter 12 - Thermodynamics>Exercise>Q 7

When a system is taken from state $i$ to state $f$ along the path $i a f$ , it is found that $Q = 50 cal$ and $W = 20 cal$ . Along the path undefined $Q = 36 cal$ . $W$ along the path $i b f$ is

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Achieve Indian Airforce Agniveer Vayu Physics Practice Book>Chapter 12 - Thermodynamics>Exercise>Q 8

An ideal gas is taken around the cycle $A B C A$ as shown in the $p V$ diagram

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The total work done by the gas during the cycle is

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Achieve Indian Airforce Agniveer Vayu Physics Practice Book>Chapter 12 - Thermodynamics>Exercise>Q 9

A thermodynamical system goes from state (i)

(p, V)

to

(2 p, V)

and (ii)

(p, V)

to

(p, 2 V)

. Work done in the two cases is

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Achieve Indian Airforce Agniveer Vayu Physics Practice Book>Chapter 12 - Thermodynamics>Exercise>Q 10

Pressure

P

, volume

V

and temperature

T

of a certain material are related by

P = \frac{α T^{2}}{V},

where

α

is constant. Work done by the material when temperature changes from

T_{0}

to

2 T_{0}

and pressure remains constant is

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Achieve Indian Airforce Agniveer Vayu Physics Practice Book>Chapter 12 - Thermodynamics>Exercise>Q 1

Assertion: The average degree of freedom per molecule for a gas is

6

. If gas performs

25 J

of work when it expands at a constant pressure then the heat absorbed by the gas is

100 J

.

Reason: First law of thermodynamics is

d Q = ∆ U + d W

where

∆ U = n C_{v} d T

.