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Assertion: The total translational kinetic energy of all the molecules of a given mass of an ideal gas is 1.5 times the product of its pressure and its volume.

Reason: The molecules of a gas collide with each other and the velocities of the molecules change due to the collision. 

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Important Questions on Kinetic Theory of Gases and Radiations

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Assuming the expression for the pressure exerted by the gas on the walls of the container, it can be shown that the pressure is 

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The temperature of a gas at pressure $P$ and volume $V$ is $27^{\circ} \mathrm{C}$. Keeping its volume constant, if its temperature is raised to $927^{\circ} \mathrm{C}$, then its pressure will be 

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If the R.M.S velocity of a gas at a given temperature (Kelvin scale) is 300 ms-1. What will be the R.M.S velocity of the gas having twice the molecular weight and half the temperature on Kelvin scale?

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The kinetic energy of one mole of a gas at standard temperature and pressure is R=8.31 J/mole-K
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Two vessels $A$ and $B$ are identical. A has 1 g hydrogen at $0^{\circ} \mathrm{C}$ and $\mathrm{B}$ has 1 g oxygen at $0^{\circ} \mathrm{C} .$ Vessel $\mathrm{A}$ contains $x$ molecules and $\mathrm{B}$ contains $y$ molecules. The average kinetic energy per molecules in $A$ is n times the average kinetic energy per molecule in $\mathrm{B}$. The value of n is

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Pressure of an ideal gas is increased by keeping the temperature constant. Then the kinetic energy of molecules

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The temperature, at which kinetic energy of a gas is doubled of its value at N.T.P., is