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If the length of a simple pendulum is comparable to the radius of the earth, then find the time period for oscillation.

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Important Questions on Oscillations

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The figure alongside shows a system of springs connected to a mass M. The amplitude of oscillation of this system would be mg3k. What will be the ratio of the amplitudes of oscillation of points A and B?
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A particle is performing simple harmonic motion with amplitude of 4 cm and time period of 12 s. The ratio between time taken by it in going from its mean position to 2 cm and from 2 cm to extreme position is
 
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Two simple harmonic motions are represented by the equations y1=0.1sin100πt+π3 and y2=0.1cosπt. The phase difference of velocity of the particle 1 with respect to the velocity of particle 2 at a time t=0 is
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A linear harmonic oscillator of force constant 2×106 N m-1 and amplitude 0.01 m has a total mechanical energy of 160 J. Its
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IMPORTANT
Two particles execute SHM of the same amplitude and frequency along the same straight line. They pass one another when going in opposite directions each time their displacement is half their amplitude. What is the phase difference between them?
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The time period of a simple pendulum is given by, T=2πlg. In an experiment, the length of the pendulum is increased by 1% while the acceleration due to gravity is also increased by 2%. The time period will,
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Above the resonant frequency,