We have to find the value 1 2 of 3 2 9 . Convert 3 2 9 into an improper fraction. 3 2 9 = 3 × 9 + 2 9 = 27 + 2 9 = 29 9 1 2 of 29 9 = 1 2 × 29 9 = 1 × 29 2 × 9 = 29 18 On dividing 29 by 18 , we get 1 as the quotient and 11 as the remainder. = 1 11 18 Therefore, the required value 1 2 of 3 2 9 is 1 11 18 .

We have to find the value 1 3 of 15 7 . The operator 'of' represents multiplication. To multiply two fractions, we multiply their numerators to get the numerator of the product and multiply their denominators to get the denominator of the product. 1 3 of 15 7 = 1 3 × 15 7 = 1 × 15 3 × 7 = 5 7 Therefore, the required value 1 3 of 15 7 is 5 7 .

We have to find the value 1 3 of 3 2 9 . Convert 3 2 9 into an improper fraction. 3 2 9 = 3 × 9 + 2 9 = 27 + 2 9 = 29 9 1 3 of 29 9 = 1 3 × 29 9 = 1 × 29 3 × 9 = 29 27 On dividing 29 by 27 , we get 1 as the quotient and 2 as the remainder. = 1 2 27 Therefore, the required value 1 3 of 3 2 9 is 1 2 27 .

Multiply and reduce to lowest form (if possible): 3 5 × 2 2 5 .

Given multiplication is 3 5 × 2 2 5 . Convert 2 2 5 into an improper fraction. 2 2 5 = 2 × 5 + 2 5 = 10 + 2 5 = 12 5 3 5 × 12 5 = 3 × 12 5 × 5 = 36 25 On dividing 36 by 25 , we get 1 as quotient and 11 as the remainder. = 1 11 25 Hence, the required value is 3 5 × 2 2 5 = 1 11 25 .

Multiply and reduce to lowest form (if possible): 3 5 × 5 6 .

Given multiplication is 3 5 × 5 6 . To multiply two fractions, we multiply their numerators to get the numerator of the product and multiply their denominators to get the denominator of the product. 3 5 × 5 6 = 3 × 5 5 × 6 = 15 30 = 1 2 Hence, the required value is 3 5 × 5 6 = 1 2 .

Multiply and reduce to lowest form (if possible): 1 4 × 32 3 .

Given multiplication is 1 4 × 32 3 . To multiply two fractions, we multiply their numerators to get the numerator of the product and multiply their denominators to get the denominator of the product. 1 4 × 32 3 = 1 × 32 4 × 3 = 32 12 = 8 3 On dividing 8 by 3 , we get 2 as quotient and 2 as the remainder. = 2 2 3 Hence, the required value is 1 4 × 32 3 = 2 2 3 .

Multiply and reduce to lowest form (if possible): 7 3 4 × 8 5 .

Given multiplication is 7 3 4 × 8 5 . Convert 7 3 4 into an improper fraction. 7 3 4 = 7 × 4 + 3 4 = 28 + 3 4 = 31 4 31 4 × 8 5 = 31 × 8 4 × 5 = 268 20 = 62 5 On dividing 62 by 5 , we get 12 as quotient and 2 as the remainder. = 12 2 5 Hence, the required value is 7 3 4 × 8 5 = 12 2 5 .