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The graph shows current v/s voltage in a series RLC A.C. circuit. The arrow indicates the direction that this curve is drawn as time progresses. In this plot, the
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Important Questions on Alternating Current

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An alternating emf of angular frequency ω is applied across an inductance. The instantaneous power developed in the circuit has an angular frequency:-
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The self-inductance of a choke coil is 10 mH. When it is connected with a 10 V DC source, then the loss of power is 20 W. When it is connected with 10 V AC source, loss of power is 10 W. The frequency of AC source will be
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In the L-C circuit shown in figure, the current is in direction shown in the figure and charges on the capacitor plates have sign shown in the figure. At this time :-
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The inductance of the oscillatory circuit of a radio station is 10 milli henry and its capacitance is 0.25µF. Taking the effect of the resistance negligible, wavelength of the broadcasted waves will be (velocity of light = 3.0 × 108 m/s, π = 3.14) : 
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A coil has an inductance of 0.7 H and is joined in series with a resistance of 220 Ω. When the alternating emf of 220 V at 50 Hz is applied to it then the phase through which current lags behind the applied emf and the wattles component of current in the circuit will be respectively : 
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When 100V D.C. is applied across a coil a current of 1A flows through it. When 100V A.C. of 50 Hz is applied to the same coil only 0.5A flows. The inductance of the coil is :- 
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In the circuit shown in the figure, the A.C. source gives a voltage V = 20 cos (2000 t) V neglecting source resistance, the voltmeter and ammeter readings will be :
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Assertion : Soft iron is used !as transformer core.
Reason : Soft iron has narrow hysteresis loop.