MEDIUM
10th CBSE
IMPORTANT
Earn 100

The sum of ages of a man and his son is 45 years. Five years ago, the product of their ages was four times the man's age at the time. Find their present ages.

Important Questions on Quadratic Equations

MEDIUM
10th CBSE
IMPORTANT
MATHEMATICS CLASS X>Chapter 4 - Quadratic Equations>EXERCISE 4.9>Q 3
The product of Shikha's age five years ago and her age 8 years later is 30, her age at both times being given in years. Find her present age.
MEDIUM
10th CBSE
IMPORTANT
MATHEMATICS CLASS X>Chapter 4 - Quadratic Equations>EXERCISE 4.9>Q 4
The product of Ramu's age (in years) five years ago and his age (in years) nine years later is 15. Determine Ramu's present age.
MEDIUM
10th CBSE
IMPORTANT
MATHEMATICS CLASS X>Chapter 4 - Quadratic Equations>EXERCISE 4.9>Q 5

Is the following situation possible? If so, determine their present ages.

The sum of the ages of two friends is 20 years. Four years ago, the product of their ages in years was 48.

MEDIUM
10th CBSE
IMPORTANT
MATHEMATICS CLASS X>Chapter 4 - Quadratic Equations>EXERCISE 4.9>Q 6
A girl is twice as old as her sister. Four years hence, the product of their ages (in years) will be 160. Find their present ages.
MEDIUM
10th CBSE
IMPORTANT
MATHEMATICS CLASS X>Chapter 4 - Quadratic Equations>EXERCISE 4.9>Q 7
The sum of the reciprocals Rehman's ages 3 years ago and five years from now is 13. Find his present age.
MEDIUM
10th CBSE
IMPORTANT
MATHEMATICS CLASS X>Chapter 4 - Quadratic Equations>EXERCISE 4.9>Q 8
If Zeba were younger by 5 years than what she really is, then the square of her age (in years) would have been 11 more than 5 times her actual age. What is her age now?
MEDIUM
10th CBSE
IMPORTANT
MATHEMATICS CLASS X>Chapter 4 - Quadratic Equations>EXERCISE 4.9>Q 9
At present Asha's age (in years) is 2 more than the square of her daughter Nisha's age. When Nisha grows to her mother's present age, Asha's age would be one year less than 10 times the present age of Nisha. Find the present ages of both Asha and Nisha.
MEDIUM
10th CBSE
IMPORTANT
MATHEMATICS CLASS X>Chapter 4 - Quadratic Equations>EXERCISE 4.10>Q 1
The hypotenuse of a right triangle is 25 cm. The difference between the lengths of the other two sides of the triangle is 5 cm. Find the lengths of these sides.