NTA - UGC NET/JRF Teaching and Research Aptitude Paper I : General>Chapter 5 - Mathematical Reasoning and Aptitude>Exercise>Q 4

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UGC NET Paper 1

IMPORTANT

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The value of $\frac{0 .1 \times 0 .1 \times 0 .1 + 0 .02 \times 0 .02 \times 0 .02}{0 .2 \times 0 .2 \times 0 .2 + 0 .04 \times 0 .04 \times 0 .04}$ is:

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Important Questions on Mathematical Reasoning and Aptitude

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UGC NET Paper 1

IMPORTANT

NTA - UGC NET/JRF Teaching and Research Aptitude Paper I : General>Chapter 5 - Mathematical Reasoning and Aptitude>Exercise>Q 5

If

2994 \div 14.5 = 172

, then

29.94 \div 1.45 = ?

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UGC NET Paper 1

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NTA - UGC NET/JRF Teaching and Research Aptitude Paper I : General>Chapter 5 - Mathematical Reasoning and Aptitude>Exercise>Q 6

When

0.232323

………. is converted into a fraction, then the result is :

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UGC NET Paper 1

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NTA - UGC NET/JRF Teaching and Research Aptitude Paper I : General>Chapter 5 - Mathematical Reasoning and Aptitude>Exercise>Q 8

The expression

(11.98 \times 11.98 + 11.98 \times x + 0.02 \times 0.02)

will be a perfect square for

X

equal to :

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UGC NET Paper 1

IMPORTANT

NTA - UGC NET/JRF Teaching and Research Aptitude Paper I : General>Chapter 5 - Mathematical Reasoning and Aptitude>Exercise>Q 9

\frac{(0 .1667) (0 .8833) (0 .3333)}{(0 .2222) (0 .6667) (0 .1250)}

is approximately equal to _____.

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UGC NET Paper 1

IMPORTANT

NTA - UGC NET/JRF Teaching and Research Aptitude Paper I : General>Chapter 5 - Mathematical Reasoning and Aptitude>Exercise>Q 10

Find the value that can replace the question mark.

$3889 + 12.952 - ? = 3854.002$

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UGC NET Paper 1

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NTA - UGC NET/JRF Teaching and Research Aptitude Paper I : General>Chapter 5 - Mathematical Reasoning and Aptitude>Exercise>Q 11

$0.04 \times 0.0162$ is equal to _____.

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UGC NET Paper 1

IMPORTANT

NTA - UGC NET/JRF Teaching and Research Aptitude Paper I : General>Chapter 5 - Mathematical Reasoning and Aptitude>Exercise>Q 12

\frac{4 .2 \times 4 .2 - 1 .9 \times 1 .9}{2 .3 \times 6 .1}

is equal to :

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UGC NET Paper 1

IMPORTANT

NTA - UGC NET/JRF Teaching and Research Aptitude Paper I : General>Chapter 5 - Mathematical Reasoning and Aptitude>Exercise>Q 13

If

\frac{144}{0 .144} = \frac{14.4}{x}

, then the value of

x

is