The value of equivalent capacitance of the combination shown in the figure, between the points $P$ and $Q$ is :

The equivalent capacitance between points A and B of the circuit shown will be :

The effective capacitance between the points $P$ and $Q$ of the arrangement, as shown in the figure is

Two spheres of radii $1 \mathrm{cm}$ and $2 \mathrm{cm}$ have been charged with $1.5 \times {10}^{-8}$and $0.3 \times {10}^{-7}$coulombs of positive charge. When they are connected with a wire, charge:

Half of the space between a parallel plate capacitor is filled with a medium of dielectric constant, $K$ parallel to the plates. If initially, the capacity was $C$, the new capacity will be:

Two capacitances C₁ and C₂ in a circuit are joined as shown in figure The potential of point . A is V₁ and that of B is V₂. The potential of point D will be : 

A circuit has a section $AB$ as shown in the figure with $E=10 \mathrm{V}, C_1=1.0\mu \mathrm{F}, C_2=2.0\mu \mathrm{F}$ and the potential difference $V_A-V_B=5 \mathrm{V}.$ The voltage across $C_1$ is :

In the circuit diagram shown, all the capacitors are in $\mu F$. The equivalent capacitance between points $A$ and $B$ is  (in $\mu F$)