Modern Approach to Chemical Calculations>Chapter 22 - Miscellaneous Objective Questions>Exercise 1>Q 210

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The van der Waals equation for $1$ mole of gas is $(p + \frac{a}{V^{2}}) (V - b) = RT$ , where,

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Important Questions on Miscellaneous Objective Questions

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IMPORTANT

Modern Approach to Chemical Calculations>Chapter 22 - Miscellaneous Objective Questions>Exercise 1>Q 211

A mixture of

H_{2}

and

O_{2}

taken in a bulb in

2 : 1

mole ratio is allowed to diffuse through a fine hole. The composition of the gases (mole ratio) coming out initially will be:

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Modern Approach to Chemical Calculations>Chapter 22 - Miscellaneous Objective Questions>Exercise 1>Q 212

For a dilute solution,

lowering of vapour pressure \propto mole fraction of the solute

or,

lowering

of vapour pressure = K \times mole fraction of the solute

, where

K

is:

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Modern Approach to Chemical Calculations>Chapter 22 - Miscellaneous Objective Questions>Exercise 1>Q 213

For ideal binary solution,

$P_{T} = X_{A} P_{A} ° + X_{B} P_{B} °$

This equation reflects

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Modern Approach to Chemical Calculations>Chapter 22 - Miscellaneous Objective Questions>Exercise 1>Q 214

Dry air is passed through a solution and then through its solvent and finally through

{CaCl}_{2}

. The ratio of weight loss in the solvent to the weight gain in

{CaCl}_{2}

gives

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Modern Approach to Chemical Calculations>Chapter 22 - Miscellaneous Objective Questions>Exercise 1>Q 215

The relative lowering of vapour pressure of an aqueous solution of urea is

0.018

. If

K_{b}

for

H_{2} O

is

0.54 ° C m^{- 1},

the elevation in boiling point will be:

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Modern Approach to Chemical Calculations>Chapter 22 - Miscellaneous Objective Questions>Exercise 1>Q 216

1

mole of

A

is allowed to decompose in a

1

litre container.

0.4

mole of

B

was produced at equilibrium. The equilibrium constant

K_{c}

for the equilibrium

A (g) ⇌ 2 B (g) + C (g),

is

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Modern Approach to Chemical Calculations>Chapter 22 - Miscellaneous Objective Questions>Exercise 1>Q 217

V_{1} mL

of

{SO}_{2},

filled in a tube at

1

atm

between a movable frictionless piston and a porous plug. The tube is left in the air till the piston stops moving. The volume

V_{1}

is found to increase to

V_{2}

. The volume

V_{2}

contains

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Modern Approach to Chemical Calculations>Chapter 22 - Miscellaneous Objective Questions>Exercise 1>Q 218

The equilibrium :

{PCl}_{5} (g) ⇌ {PCl}_{3} (g) + {Cl}_{2} (g)

, may be shifted to the right if