These are $3$ elements $\mathrm{A}, \mathrm{B}$ and $\mathrm{C}$. Their atomic number are ${\mathrm{Z}}_1, {\mathrm{Z}}_2, {\mathrm{Z}}_3$, respectively. If ${\mathrm{Z}}_3-{\mathrm{Z}}_1=2$ and $\frac{Z_1+Z_3}{2}=Z_2$ and the electronic configuration of an element $\mathrm{C}$ is  $\left[\mathrm{Ar}\right]3{\mathrm{d}}^{2}4{\mathrm{s}}^2$ the correct order of atomic radius is:

$\mathrm{K}\stackrel{\mathrm{a}}{⟶}{\mathrm{K}}^{+}\stackrel{\mathrm{b}}{⟶}{\mathrm{K}}^{+2}$

$\mathrm{Ca}\stackrel{\mathrm{c}}{\to }{\mathrm{Ca}}^{+}\stackrel{\mathrm{d}}{\to }{\mathrm{Ca}}^{+2}$

If $\mathrm{a}, \mathrm{b}, \mathrm{c}, \mathrm{d}$ are ionisation energies, the which of the following order is not correct -

Electronic configurations is:

$\mathrm{A}-1{\mathrm{s}}^{2}2{\mathrm{s}}^{2}2{\mathrm{p}}^1$

$\mathrm{B}-1{\mathrm{s}}^{2}2{\mathrm{s}}^{2}2{\mathrm{p}}^{6}3{\mathrm{s}}^{2}3{\mathrm{p}}^1$

$\mathrm{C}-1{\mathrm{s}}^{2}2{\mathrm{s}}^{1}2{\mathrm{p}}^1$

$\mathrm{D}-1{\mathrm{s}}^{2}2{\mathrm{s}}^{2}2{\mathrm{p}}^{5}3{\mathrm{s}}^1$

Then, which among these will belong to the same group in the periodic table?