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Unpolarized light of intensity is passing through two polaroids kept at an angle with each other. What will be the final intensity?
(a)
(b)
(c)
(d)

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Important Questions on Wave Optics
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A single slit is of width 0.5 mm. Distance of screen from slit is 1 m. Second maxima in diffraction pattern is at distance 2 mm from centre. What is wavelength of light ?

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In YDSE wavelength of light used is 600 nm. At a point intensity is 50% of maximum value. What is path difference at that point :-

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A unpolarised light is passing through three pohroids as shown final intensity will be :-

EASY
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In a single slit diffraction, slit width is and distance of first minima from central position is . If screen distance is , then wave length of light is :

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In , the distance between slits is , the distance between slit and screen is and wavelength of monochromatic light incident on slit is . Find the phase difference between the waves at a point from midpoint?

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In an interference pattern of two waves, the fringe width is . If the frequency of source is doubled, then fringe width becomes,

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The intensity of the central fringe obtained in the interference pattern due to two identical slit sources is . When one of the slits is closed, then the intensity at the same point is . Then, the correct relation between and is,

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In double slit experiment, the angular width of the fringes is 0.20° for the sodium light (). In order to increase the angular width of the fringes by 10%, the necessary change in the wavelength is :
