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Unpolarized light of intensity I0 is passing through two polaroids kept at an angle 15° with each other. What will be the final intensity?

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Important Questions on Wave Optics

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A single slit is of width 0.5 mm. Distance of screen from slit is 1 m. Second maxima in diffraction pattern is at distance 2 mm from centre. What is wavelength of light ?
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In YDSE wavelength of light used is 600 nm. At a point intensity is 50% of maximum value. What is path difference at that point :-    
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A unpolarised light is passing through three pohroids as shown final intensity will be :-

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In a single slit diffraction, slit width is 0.6 mm and distance of first minima from central position is 1 mm. If screen distance is 1.2 m, then wave length of light is :
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In YDSE, the distance between slits is 0.2 mm, the distance between slit and screen is 2 m and wavelength of monochromatic light incident on slit is 600 nm. Find the phase difference between the waves at a point 2 cm from midpoint?
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In an interference pattern of two waves, the fringe width is β. If the frequency of source is doubled, then fringe width becomes,
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The intensity of the central fringe obtained in the interference pattern due to two identical slit sources is I. When one of the slits is closed, then the intensity at the same point is I0. Then, the correct relation between I and I0 is,
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In double slit experiment, the angular width of the fringes is 0.20° for the sodium light (λ=5890 Ao). In order to increase the angular width of the fringes by 10%, the necessary change in the wavelength is :