EASY
JEE Main/Advance
IMPORTANT
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What can be concluded about the value of H and S from this graph?

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Important Questions on Thermodynamics

EASY
JEE Main/Advance
IMPORTANT
For which of the following processes, total entropy of universe increases.
MEDIUM
JEE Main/Advance
IMPORTANT
1 mole of an ideal gas at 25°C is subjected to expand reversibly ten times of its initial volume. The change in entropy due to expansion is:
HARD
JEE Main/Advance
IMPORTANT
The standard enthalpy of formation of propene, C3H6, is +20.6 kJ/mole. Calculate the heat of combustion of one mole of C3H6. The heats of formation of CO2g and H2Ol are -394 kJ/mole and -285.8 kJ/mole respectively.
HARD
JEE Main/Advance
IMPORTANT

The fat, glyceryl trioleate, is metabolized via the following reaction. Given the enthalpies of formation, calculate the energy kJ liberated when 1.00 g of this fat reacts.

(Atomic weights: C=12.01, H=1.008, O=16.00)

C57H107O6s+80 O2g57 CO2+52H2Ol

H°C57H107O6=-70870 kJ/mole

H°H2Ol=-285.8 kJ/mole

H°CO2g=-393.5 kJ/mole

MEDIUM
JEE Main/Advance
IMPORTANT

Using the enthalpies of formation, calculate the energy kJ released when 3.00 g of NH3g reacts according to the following equation.

(Atomic weights: B=10.81,O=16.00,H=1.008)

4NH3g+5O2g4NOg+6H2Og

H°NH3g=-46.1 kJ/mole

H°NOg=+90.2 kJ/mole

H°H2Og=-241.8 kJ/mole

MEDIUM
JEE Main/Advance
IMPORTANT
A sheet of 15.0 g of gold at 25.0°Cis placed on a 30.0 g sheet of copper at 45.0°C. What is the final temperature of the two metals assuming that no heat is lost to the surroundings. The specific heats of gold and copper are 0.129 J/g°C and 0.385 J/g°C respectively.
MEDIUM
JEE Main/Advance
IMPORTANT

Calculate the heat of combustion kJ of propane, C3H8 using the listed standard enthalpy of reaction data:

C3H8g+5O2g3CO2g+4H2Og

3Cs+4H2gC3H8g       H°/KJ=-103.8

Cs+O2gCO2g              H°/KJ=-393.5

H2g+12O2gH2Og       H°/KJ=-241.8

MEDIUM
JEE Main/Advance
IMPORTANT

Calculate the value of H°/kJ for the following reaction using the listed thermochemical equations:

2Cs+H2gC2H2g

2C2H2g+5O2g4CO2g+2H2Ol    H°/kJ=-2600 kJ

Cs+O2gCO2g                                      H°/kJ=-390 kJ

2H2g+O2g2H2Ol                                H°/kJ=-572 kJ