Hess's Law of Constant Heat Summation

Author:Embibe Experts
JEE Main/Advanced
IMPORTANT

Important Questions on Hess's Law of Constant Heat Summation

MEDIUM
IMPORTANT

Consider the following data

AOH3+4HClHACl4+3H2O              H°=-xkJ

AOH3+4HBrHABr4+3H2O             H°=-ykJ

AOH3+4HIHAl4+3H2O                   H°=-zkJ

(x,y and z are positive number)

Experiment I: 0.4 kJ is absorbed when one mol of HABr4 was mixed with 4 mol of HCl and % conversion of HABr4 into HACl4 is 5% (Hypothetical)

Experiment II: 0.8 kJ is released when one mol of HABr4 was mixed with 4 mol of HI and % conversion of HABr4 into HAI4 is 8%.

If one mol of HAl4 is mixed with 4 mol of HCl and conversion of HAl4 into HACl4 is 10% then in this process

MEDIUM
IMPORTANT

Given that

AsAl  ΔH=x

AIAg  ΔH=y

The heat of sublimation of A will be

EASY
IMPORTANT

Hi° of water is -285.8 kJ mol-1. If enthalpy of neutralization of strong monoacid with strong mono base is -57.3 kJ mol-1,ΔHf° of OH- ion will be

HARD
IMPORTANT

1 mol of hydrocarbon P (contains C and H only) required 240 g of oxygen (O2) for complete combustion at standard state. If at standard state heat of combustion of P(l) is –3350 kJ/mol while heat of formation of CO2 (g), H2O(l) and P(l) are –400 kJ/mol, –300 kJ/mol and 50 kJ/mol. The molar mass of P is (in g/mol)