Chemical Reactions of Diazonium Salts

Benzenediazonium chloride can be converted into benzene on treatment with

Statement-1: Aniline on reaction with ${\mathrm{NaNO}}_2/\mathrm{HCl}$ at $0 °\mathrm{C}$ followed by coupling with $\mathrm{\beta }$-naphthol gives a dark blue precipitate.

Statement-2 : The colour of the compound formed in the reaction of aniline with ${\mathrm{NaNO}}_2/\mathrm{HCl}$ at $0 °\mathrm{C}$ followed by coupling with $\mathrm{\beta }$-naphthol is due to the extended conjugation.

Which of the following statement is CORRECT about product?

Observe the following reaction and determine True statement

${\mathrm{C}}_6{\mathrm{H}}_5{\mathrm{N}}_2\mathrm{Cl}\stackrel{{\mathrm{SnCl}}_2/\mathrm{HCl}}{\to }\left(\mathrm{A}\right)\stackrel{{\mathrm{C}}_6{\mathrm{H}}_5\mathrm{CHO}}{\to }\left(\mathrm{B}\right)$

The product $\left(\mathrm{B}\right)$ in the above sequence of reaction is

Complete reduction of benzene-diazonium chloride with $\mathrm{Zn}/\mathrm{HCl}$ gives:

The major product of the following reaction is:

Coupling reaction takes place when benzene diazonium chloride is treated with:

$\mathrm{Ph}-{\mathrm{NO}}_2\stackrel{\mathrm{Sn}/\mathrm{HCl}}{\to }\underset{\mathrm{HCl}, 0°\mathrm{C}-5°\mathrm{C}}{\overset{{\mathrm{NaNO}}_2}{\to }}\underset{\mathrm{Ph}-\mathrm{OH}}{\overset{\mathrm{Basic} \mathrm{medium}}{\to }}$ Product $\mathrm{Y}$

Find the molecular weight of $\mathrm{Y}$ report your answer as $\frac{\mathrm{Molecular} \mathrm{weight}}{2}.$

 Product $\mathrm{Z}$

Find the molecular weight of $\mathrm{Z}.$

How many toluidines on reaction with ${\mathrm{NaNO}}_2/\mathrm{HCl}$ followed by ${\mathrm{H}}_3{\mathrm{PO}}_2$ treatment gives toluene.

The major product $\mathrm{Y}$ in the following sequence of reaction is:

Aniline $\underset{\left(\mathrm{ii}\right) \mathrm{CuCN}/\mathrm{KCN}}{\overset{\left(\mathrm{i}\right) {\mathrm{NaNO}}_2/\mathrm{HCl}, 273 \mathrm{K}}{\to }}\left(\mathrm{X}\right)\underset{\left(\mathrm{ii}\right) {\mathrm{H}}_2\mathrm{O}}{\overset{\left(\mathrm{i}\right) \mathrm{DIBAL}-\mathrm{H}}{\to }}\left(\mathrm{Y}\right)$

The structure of the final product $\left(\mathrm{Y}\right)$ formed in the following reaction sequence is:

Para toluidine is treated with ${\mathrm{HNO}}_2$ at ice-cold conditions and then boiled with water. The final product obtained is:

 (major product) $\mathrm{X}$ will be:

 (major product) $\mathrm{X}$ will be:-

${\mathrm{C}}_6{\mathrm{H}}_5{\mathrm{NH}}_2\underset{0-5°\mathrm{C}}{\overset{{\mathrm{NaNO}}_2}{\to }}\mathrm{X}\underset{△}{\overset{{\mathrm{H}}_2\mathrm{O}}{\to }}\mathrm{Y},$ the product $\mathrm{Y}$ is:

 $, \mathrm{P}$ is:

A solution contains $1 \mathrm{g} \mathrm{mol}$ each of $\mathrm{p}-$toluene diazonium chloride and$\mathrm{p}-$nitrophenyl diazonium chloride. To this $1 \mathrm{g} \mathrm{mol}$ of an alkaline solution of phenol is added. Predict the major product. Explain your answer. 

Which of the following compound will not undergo azo coupling reaction with benzene diazonium chloride.