Preparation of Diazonium Salts

How will you convert aniline into benzyl alcohol.

How to convert Benzene into 3-Bromophenol.

How will you convert 2-Bromo-4-aminotoluene into 2-Bromobenzoic acid.

Convert 3-methylaniline into 3-nitrotoluene

Incorrect statement(s) regarding this reaction

Possible product(s) is/are:

Predict respectively $\mathrm{\prime }\mathrm{X}\mathrm{\prime }$ and $\mathrm{\prime }\mathrm{Y}\mathrm{\prime }$ in the following reactions

$\mathrm{Ar}-{\mathrm{NH}}_2\stackrel{\mathrm{X}}{\to }\mathrm{Ar}-{\mathrm{N}}^{\oplus }\equiv \mathrm{N}-{\mathrm{Cl}}^{⊝}\mathrm{ }\stackrel{\mathrm{Y}}{\to }\mathrm{Ar}-\mathrm{Cl}\mathrm{ }$

${\mathrm{N}}_2$ gas is liberated when $[\mathrm{H}\mathrm{C}\mathrm{l}+\mathrm{N}\mathrm{a}\mathrm{N}{\mathrm{O}}_2]$ reacts with the following compound

A. $\mathrm{C}{\mathrm{H}}_3\mathrm{C}{\mathrm{H}}_2\mathrm{N}{\mathrm{H}}_2$

B. Urea

C. $\mathrm{C}{\mathrm{H}}_3\mathrm{C}\mathrm{O}\mathrm{N}{\mathrm{H}}_2$

D. ${\mathrm{C}}_6{\mathrm{H}}_5\mathrm{N}{\mathrm{H}}_2$

The answer is

A compound $\left[\mathrm{A}\right]$ on treatment with excess ${\mathrm{N}\mathrm{H}}_3$ gives $\left[\mathrm{B}\right]$ in presence of ${\mathrm{Z}\mathrm{n}\mathrm{C}\mathrm{l}}_2$ at $300°\mathrm{C}$. $\left[\mathrm{B}\right]$ on treatment with ${\mathrm{C}\mathrm{H}\mathrm{C}\mathrm{l}}_3$ and $\mathrm{K}\mathrm{O}\mathrm{H}$ gives phenyl isocyanide. The diazonium salt from $\left[\mathrm{B}\right]$ gives $\left[\mathrm{C}\right]$ with ethanol. The incorrect option is:

${\mathrm{C}}_6{\mathrm{H}}_6\mathrm{ }\underset{{\mathrm{H}}_2\mathrm{S}{\mathrm{O}}_4}{\stackrel{\mathrm{H}\mathrm{N}{\mathrm{O}}_3}{\to }}\hspace{1em}\mathrm{ }\underset{\mathrm{F}\mathrm{e}}{\stackrel{\mathrm{C}{\mathrm{l}}_2}{\to }}\mathrm{ }\left[\mathrm{X}\right]\underset{\mathrm{N}\mathrm{a}\mathrm{O}\mathrm{H}}{\stackrel{\mathrm{S}\mathrm{n}}{\to }}\mathrm{ }\left[\mathrm{Y}\right]$
$\underset{\mathrm{\Delta }}{\stackrel{\mathrm{H}\mathrm{C}\mathrm{l}}{\to }}\mathrm{ }\hspace{1em}\stackrel{\bar{\mathrm{O}}\mathrm{H}}{\to }\hspace{1em}\left[\mathrm{Z}\right]\mathrm{ }\stackrel{\mathrm{H}\mathrm{N}{\mathrm{O}}_2,\mathrm{ }{\mathrm{H}}_3\mathrm{P}{\mathrm{O}}_2}{\to }\mathrm{ }\left[\mathrm{P}\right]$
Which of the following are correct?

When aniline is treated with a mixture of sodium nitrite and hypophosphorus acid, the product formed is

For the preparation of p-nitroiodobenzene from p-nitroaniline, the best method is

In order to convert aniline into chlorobenzene the reagent used is

The ion formed by the reaction of $\mathrm{H}\mathrm{N}{\mathrm{O}}_2$ and ${\mathrm{H}}_2\mathrm{S}{\mathrm{O}}_4$is

${\mathrm{N}}_2$ gas is liberated when $\left[\mathrm{H}\mathrm{C}\mathrm{l}+\mathrm{N}\mathrm{a}\mathrm{N}{\mathrm{O}}_2\right]\mathrm{ }$reacts with which of the following compounds?

(A) $\mathrm{C}{\mathrm{H}}_3\mathrm{C}{\mathrm{H}}_2\mathrm{N}{\mathrm{H}}_2$ (B) Urea

(C) $\mathrm{C}{\mathrm{H}}_3\mathrm{C}\mathrm{O}\mathrm{N}{\mathrm{H}}_2$ (D) ${\mathrm{C}}_6{\mathrm{H}}_5\mathrm{N}{\mathrm{H}}_2$

When aniline is treated with sodium nitrite and hydrochloric acid at $0\mathrm{℃}$, it gives

Which will not go for diazotization?

Aniline in a set of reactions yielded a product $\mathrm{D}$.



The structure of the product $\mathrm{D}$ would be: