Quantum Mechanical Model of the Atom

The total number of atomic orbitals in the fourth energy level of an atom is :

Consider the following sets of quantum numbers :

which of the following sets of quantum number is not possible ?

The orientation of an atomic orbital is governed by

The number of orbitals possible for the following quantum numbers is/are

$\mathrm{n}=3,\hspace{0.17em}\hspace{0.17em}\mathrm{l}=2, \mathrm{m}=+2$

The position of both, an electron and a helium atom is known within $1.0 \mathrm{nm}$. Further, the momentum of the electron is known with in $5.0\times {10}^{-26}\mathrm{kg}{\mathrm{ms}}^{-1}$.The minimum uncertainty in the measurement of the momentum of the helium atom is

The number of spherical nodes in 3p orbitals are

The electron was shown experimentally to have wave properties by

The relation between ${\mathrm{n}}_{\mathrm{m}}$ (${\mathrm{n}}_{\mathrm{m}}=$the number of permissible values of magnetic quantum number $\left(\mathrm{m}\right)$) for a given value of azimuthal quantum number $\left(\mathrm{l}\right)$, is

The number of correct statements from the following is ...........
A. For $1\mathrm{s}$ orbital, the probability density is maximum at the nucleus
B. For $2\mathrm{s}$ orbital, the probability density first increases to maximum and then decreases sharply to zero.
C. Boundary surface diagrams of the orbitals encloses a region of $100\%$ probability of finding the electron.
D. $\mathrm{p}$ and $\mathrm{d}$-orbitals have $1$ and $2$ angular nodes respectively
E. probability density of $\mathrm{p}$-orbital is zero at the nucleus
 

The number of atomic orbitals from the following having $5$ radial nodes is
$7\mathrm{s}, 7\mathrm{p}, 6\mathrm{s}, 8\mathrm{p}, 8\mathrm{d}$

The orbital angular momentum of an electron in $3 \mathrm{s}$ orbital is $\frac{\mathrm{xh}}{2\mathrm{\pi }}$. The value of $\mathrm{x}$ is (nearest integer)

The wavelength of an electron of kinetic energy $4.50\times {10}^{-29} \mathrm{J}$ is $\mathrm{\_\_\_\_\_\_\_\_}\times 10–5 \mathrm{m}.$ (Nearest integer) Given: mass of electron is$9\times 10–31 \mathrm{kg}, \mathrm{h}=6.6\times 10–34 \mathrm{Js}$

If the radius of the first orbit of hydrogen atom is $a_{\mathit{0}}$, then de Broglie’s wavelength of electron in $3^{\mathrm{rd}}$ orbit is

The orbital angular momentum of electron in $3\mathrm{s}$ is $\frac{\mathrm{xh}}{2\mathrm{\pi }}$. Then the value of x is :