Kohlrausch's Law and its Application

Find the solubility product of a saturated solution of ${\text{Ag}}_2{\text{CrO}}_4$  at 298 K in water if the emf of the cell $\text{Ag}\left|{\text{Ag}}^{+}\left({\text{Ag}}_2{\text{CrO}}_4\right)\right|\left|{\text{Ag}}^{+}\left(0\text{.1}\text{M}\right)\right|\text{Ag}\left(\text{s}\right)$ is 0.164 V at 298 K.

Calculate ${\Lambda }^{\text{o}}{}_{\text{HOAC}}$  at infinite dilution in  ${\text{H}}_{\text{2}}\text{O}$ at  $\text{25}°\text{C}$:

The molar conductance and the specific conductance of an electrolyte are related by the formula

$0.05 \mathrm{M}$ $\mathrm{NaOH}$ offered a resistance of $31.2 \mathrm{ohm}$ in a conductivity cell having a cell constant of $0.38 {\mathrm{cm}}^{-1}$. Calculate the molar conductivity of $\mathrm{NaOH}$ solution.

Which statement is not correct for Kohlrausch law?

If the value of molar conductivities at infinite dilution for ${\mathrm{CH}}_3\mathrm{COOH}$, $\mathrm{HCl}$ and $\mathrm{NaCl}$ are $390.5, 425.4$and $126.4 \mathrm{S} {\mathrm{cm}}^2{\mathrm{mol}}^{-1}$ respectively at $298 \mathrm{K}$. Calculate the molar conductivity at infinite dilution of ${\mathrm{CH}}_3\mathrm{COONa}$ in $\mathrm{S} {\mathrm{cm}}^2{\mathrm{mol}}^{-1}$. (Just mention the value, no requirement of units in the answer).

The molar conductivity of a solution of a weak acid $\mathrm{HX} (0.01 \mathrm{M})$ is $10$ times smaller than the molar conductivity of a solution of a weak acid $\mathrm{HY} (0.10 \mathrm{M})$. If $\mathrm{\lambda }{°}_{{\mathrm{X}}^{-}}=\mathrm{\lambda }{°}_{{\mathrm{Y}}^{-}}$, the difference in their $\mathrm{pKa}$ values, ${\mathrm{pK}}_{\mathrm{a}}\left(\mathrm{HX}\right)-{\mathrm{pK}}_{\mathrm{a}}\left(\mathrm{HY}\right)$, is (consider degree of ionization of both acids to be $<<1$)

The $\mathrm{pH}$ of a $0.1$ molar solution of the acid $\mathrm{HQ}$ is $3$ . The value of the ionisation constant, ${\mathrm{K}}_{\mathrm{a}}$ of this acid is :

The molar conductivities of $\mathrm{KCl}, \mathrm{NaCl}$ and ${\mathrm{KNO}}_3$ at infinite dilution are $152, 128$ and $111 {\mathrm{Scm}}^2 {\mathrm{mol}}^{–1}$ respectively. The molar conductivity of ${\mathrm{NaNO}}_3$ at infinite dilution is :-

The specific conductance of $\mathrm{AgCl}$ solution in water was determined to be $1.8 \times {10}^{–6} {\mathrm{\Omega }}^{–1} {\mathrm{cm}}^{–1} \mathrm{at} 298\mathrm{K}$. The molar conductances at infinite dilution of ${\mathrm{Ag}}^{+}$ & ${\mathrm{Cl}}^{–}$ are $67.9 \& 82.1 {\mathrm{\Omega }}^{-1}1{\mathrm{cm}}^2{\mathrm{mol}}^{–1}$. What is  the solubility of $\mathrm{AgCl}$ in water ?

The maximum molar conductivities of ${\mathrm{X}}^{+3}$ and ${\mathrm{Y}}^{-}$ ions are $200$ and $100 \mathrm{S} {\mathrm{cm}}^2 {\mathrm{mol}}^{-1}$ respectively. The molar conductivity of ${\mathrm{XY}}_3$ at infinite dilution is :-

The specific conductance of a saturated $\mathrm{AgCl}$ solution is found to be $1.86\times {10}^{-6} \mathrm{S} {\mathrm{cm}}^{-1}$ and that for water is $6.0\times {10}^{-8} \mathrm{S} {\mathrm{cm}}^{-1}$. The molar conductance of $\mathrm{AgCl}$ at infinite dilution is $180 \mathrm{S} {\mathrm{cm}}^2{\mathrm{mol}}^{-1}$. The solubility of $\mathrm{AgCl}$ is:

The equivalent conductances at infinite dilution $\left({\mathrm{\Lambda }}_0\right)$ for electrolytes $\mathrm{BA}$ and $\mathrm{CA}$ are $140$ and $120$ $\mathrm{S} {\mathrm{cm}}^2 {\mathrm{eq}}^{-1}$. The equivalent conductance at infinite dilution for $\mathrm{BX}$ is $198 \mathrm{S} {\mathrm{cm}}^2 {\mathrm{eq}}^{-1}$. The ${\mathrm{\Lambda }}_0($in $\left.\mathrm{S} {\mathrm{cm}}^2 {\mathrm{eq}}^{-1}\right)$ of $\mathrm{CX}$ is :-

For saturated solution of ${\mathrm{Ag}}_2{\mathrm{CrO}}_4$ at infinite dilution ${\left({\mathrm{\lambda }}_{\mathrm{m}}^{\infty }\right)}_{{\mathrm{Ag}}^{+}}=120{\mathrm{ohm}}^{-1}{\mathrm{cm}}^2 {\mathrm{mol}}^{-1}$ and${\left({\mathrm{\lambda }}_{\mathrm{m}}^{\infty }\right)}_{{\mathrm{CrO}}_4^{2-}}=260 {\mathrm{ohm}}^{-1} {\mathrm{cm}}^2 {\mathrm{mol}}^{-1}$specific conductance of solution is $2\times {10}^{-2} {\mathrm{ohm}}^{-1} {\mathrm{cm}}^{-1}$ Calculate the solubility product of ${\mathrm{Ag}}_2{\mathrm{CrO}}_4$ :-

If equivalent conductance of $1 \mathrm{M}$ benzoic acid is $12.8 \mathrm{ohm}{}^{-1} {\mathrm{cm}}^2{\mathrm{eq}}^{-1}$ and the equivalent conductance of benzoate ion and ${\mathrm{H}}^{+}$ ion at infinite dilution are $42$ and $288.42 {\mathrm{ohm}}^{-1} {\mathrm{cm}}^2{\mathrm{eq}}^{-1}$ respectively then its degree of dissociation is :-

The resistance of $0.1 \mathrm{N}$ solution of formic acid is $200$ ohm and cell constant is $2.0 {\mathrm{cm}}^{-1}$. The equivalent conductivity (in $\mathrm{S} {\mathrm{cm}}^2 {\mathrm{eq}}^{-1}$) of $0.1 \mathrm{N}$ formic acid is :-

The molar conductivity of acetic acid at infinite dilution is $390.7 {\mathrm{Scm}}^2{\mathrm{mol}}^{-1}$. Conductivity of  $0.1 \mathrm{M}$ acetic acid solution is $5.2 {\mathrm{Scm}}^2 {\mathrm{mol}}^{-1}$, find out degree of dissociation of acetic acid :-

Consider the galvanic cell, $\mathrm{Pt}\left(\mathrm{s}\right)\overline{){\mathrm{H}}_2(1 \mathrm{bar})\overline{)\mathrm{HCl}\left(\mathrm{aq}\right)(1 \mathrm{M})\overline{)\mathrm{Cl}(1 \mathrm{bar})\overline{)\mathrm{Pt}\left(\mathrm{s}\right)}}}}$. After running the cell for sometime, the concentration of the electrolyte is automatically raised to $3 \mathrm{M} \mathrm{HCl}$. Molar conductivity of the $3 \mathrm{M} \mathrm{HCl}$ is about $240 \mathrm{S} {\mathrm{cm}}^2 {\mathrm{mol}}^{-1}$ and limiting molar conductivity of $\mathrm{HCl}$ is about $420 \mathrm{S} {\mathrm{cm}}^2{\mathrm{mol}}^{-1}$. If ${\mathrm{K}}_{\mathrm{b}}$ of water is $0.52 \mathrm{K} \mathrm{kg} {\mathrm{mol}}^{-1}$, calculate the boiling point of the electrolyte at the end of the experiment.

At ${25}^{°}\mathrm{C}$ the molar conductance of $0.007 \mathrm{M}$ hydrofluoric acid is $150 \mathrm{mho} {\mathrm{cm}}^2 {\mathrm{mol}}^{-1}$ and its ${{\mathrm{\Lambda }}^{°}}_{\mathrm{m}}=500 \mathrm{mho} {\mathrm{cm}}^2 {\mathrm{mol}}^{-1}$. The value of the dissociation constant of the acid at the given concentration at ${25}^{°}\mathrm{C}$ is