Percentage Composition, Empirical FORMULA AND Molecular Formula

Author:K L Chugh
11th West Bengal Board
IMPORTANT

Important Questions on Percentage Composition, Empirical FORMULA AND Molecular Formula

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IMPORTANT

Two elements, X (atomic weight =75) and Y (atomic weight =16) combine to give a compound having 75.8 % of X. The compound is:

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What is meant by empirical and molecular formula of a compound? Explain with an example.

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What is meant by empirical and molecular formula of a compound. How are the two related to each other?

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A crystalline salt on being rendered anhydrous, loses 51.2 % of its weight. The anhydrous salt on analysis gave the following percentage composition: Mg=20.0 %;S=26.66 %;O=53.33 %. Calculate the molecular formula of the anhydrous salt and the crystalline salt. Molecular mass of the anhydrous salt is 120.

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1.615 g of an anhydrous salt was placed in moist air. After a few days, it was found to be 2.875 g. Assuming that complete hydration has taken place, calculate the simplest formula of the hydrated salt. The percentage composition of anhydrous salt is: Zn=40.6 %; S=19.8 %; O=39.6 %.

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A compound contains 4.07 % hydrogen, 24.27 % carbon and 71.65 % chlorine. Its molar mass is 98.96 g. What are its empirical and molecular formulas?

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The percentage composition of sodium phosphate as determined by analysis is 42.1 % sodium, 18.9 % phosphorus and 39 % oxygen. Find the empirical formula of the compound.

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An organic compound contains carbon, hydrogen and oxygen. 1.80 g of the substance on combustion gave 2.64 g of carbon dioxide and 1.08 g of water. Calculate the empirical formula of the compound.

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Calculate the percentage of water of crystallization in the sample of Blue Vitriol (CuSO4.5H2O).

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The compound Na2B4O7.10H2O is commonly known as borax. Calculate the percentage of boron (B) in borax (H=1, B=11, O=16, Na=23).