Construction of Triangles (Special Cases)
Construction of Triangles (Special Cases): Overview
This topic helps us understand the different cases of the construction of triangles. Four cases are explained for the construction of different types of triangles. It also provides us with the step-by-step explanation for the construction of triangles.
Important Questions on Construction of Triangles (Special Cases)
Construct an equilateral triangle of side and construct another triangle similar to , such that each of its sides is of the sides of .

Construct a segment of a circle on a chord of length and containing an angle of

Construct a segment of a circle on a chord of length and containing an angle of

Is it possible to construct triangles with the given measurement

What is the measure of the side of an equilateral triangle constructed rounded off to one decimal place in , if each of whose altitudes measures ?

Constructing a triangle in which and is possible.

Construction of , in which , and is possible.

A triangle, , with and can be constructed.

We can construct a in which and the perpendicular from the vertex to base is .

A triangle can be constructed in which and .

If all the angles of a triangle are given, we can construct a unique triangle.

Which of these triangle can be constructed?

We can construct a right triangle whose one side is and the sum of the other side and the hypotenuse is .

The incorrect step(s) of construction of a whose perimeter is and the base angles are and is/are

What is the measure of the side of an equilateral triangle constructed rounded off to one decimal place in , if each of whose altitudes measures ?

We can construct a triangle whose perimeter is and the base angles are and .

We can construct a right triangle whose base is and sum of its hypotenuse and other side is .

We can construct an equilateral triangle, given its side.

A/An _____ Triangle can be constructed when the length of only one side is given.

Steps of construction of triangle in which and are given below.
Draw .
Construct
Cut off on . Join .
Draw perpendicular bisector for , meeting produced at .
Join . Then is the required triangle.
Which of the above step(s) is/are incorrect?
