Mean Deviation

Find the mean deviation(in decimal) about the mean for the following data:

$6,8, 4, 13, 9, 5, 16, 19$.

From the following data, find the line of regression of $x$ on $y$ and estimate the value of $x$, if $y=90$:

Coefficient of correlation $r$ between $x$ and $y$ is $0.8$.

Find the coefficient of correlation between $x$ and $y$ from the following data:

mean deviation from the mean for the data

$4, 7, 8, 9, 10, 12, 13, 17$ is _____

If the variables $x$ and $y$ are related by $2 x+5 y=13$ and if $\overline{x}=5$, mean deviation of $x$ about its mean is $3$, find the mean deviation about the mean of $y$.

Two variables $x$ and $y$ an related by $3 y=2 x-43.2$. If mean deviation about the median of $x$ is $3.2$ find the mean deviation about the median of $y$ .

Two variables $x$ and $y$ are related by $\frac{x}{5}+\frac{y}{3}=-22$. If mean deviation about mean of $x$ is $25$, find the mean deviation about mean of $y$.

If $3 x+7 y=21$ is the relation between two variables $x$ and $y$ and $MD$ of $x$ about its mean is $3$, calculate the $MD$ of $y$ about its mean.

There are $9$ terms in a sequence which is in descending order. Its mean value is $90$. If we add $50$ to each term and then each term is divided by $3$, we get a new mean $\mathrm{M}$. What is the difference between $\mathrm{M}$ and the original mean?

At the end of the year, Mahesh analysed his last five-month salary figures. He found the mean and median salary figures as $\mathrm{Rs}. 6 \mathrm{lacs}$ and the only mode salary figure as $\mathrm{Rs}. 8 \mathrm{lacs}$. If all his salaries are in lacs then what is the sum of the highest and the lowest salary earned by him?

The mean deviation from the median for the following distribution (corrected to two decimals) is

The mean deviation about the mean for the following data is: 

The mean deviation from the mean of the series $\left(a\right), (a+d), (a+2d),\dots \dots \dots ,(a+2nd)$ is

For calculating mean deviation, deviations cannot be taken from any average.

Calculation of mean deviation is based on observations unlike range or quartile deviation which considers only limits.

While measuring dispersion using mean deviation, the value is not affected as much by the extreme values.

The mean deviation of the data $3, 10, 10, 4, 7, 10, 5$ is:

Find the mean deviation from the mean for the following data. Write the answer upto 2 decimal places.

Find the mean deviation from the mean for the following data:

Calculate the mean deviation from the mean for the following data:

$36, 72, 46, 42, 60, 45, 53, 46, 51, 49$.

Write the answer in decimal form.