Mean Deviation

$38,70,48,34,63,42,55,44,53,47$

Find the number of observations lying between $\overline{x}-M.D$ and $\overline{x}+M.D$ where $M.D$ is the mean deviation from the mean.

$22,24,30,27,29,31,25,28,41,42$

Find the number of observations lying between $\overline{x}-M.D$ and $\overline{x}+M.D$ where $M.D$ is the mean deviation from the mean.

$34,66,30,38,44,50,40,60,42,51$

Find the number of observations lying between $\overline{x}-M.D$ and $\overline{x}+M.D$ where $M.D$ is the mean deviation from the mean.

Calculate mean deviation from the median of the following data:

$\begin{array}{|lccccc|}\hline \text{ Class interval: }& 0-6& 6-12& 12-18& 18-24& 24-30\\ \text{ Frequency: }& 4& 5& 3& 6& 2\\ \hline\end{array}$

The age distribution of $100$ life-insurance policy holders is as follows:

$\begin{array}{|lcccccccc|}\hline \begin{array}{l}\mathrm{Age}(\mathrm{on}nearest\\ \mathrm{birth}\mathrm{day})\end{array}& \mathbf{17}\mathbf{-}\mathbf{19}\mathbf{.}\mathbf{5}& \mathbf{20}\mathbf{-}\mathbf{25}\mathbf{.}\mathbf{5}& \mathbf{26}\mathbf{-}\mathbf{35}\mathbf{.}\mathbf{5}& \mathbf{36}\mathbf{-}\mathbf{40}\mathbf{.}\mathbf{5}& \mathbf{41}\mathbf{-}\mathbf{50}\mathbf{.}\mathbf{5}& \mathbf{51}\mathbf{-}\mathbf{55}\mathbf{.}\mathbf{5}& \mathbf{56}\mathbf{-}\mathbf{60}\mathbf{.}\mathbf{5}& \mathbf{61}\mathbf{-}\mathbf{70}\mathbf{.}\mathbf{5}\\ \mathrm{No}.\mathrm{of}persons& 5& \mathbf{16}& \mathbf{12}& \mathbf{26}& \mathbf{14}& \mathbf{12}& \mathbf{6}& \mathbf{5}\\ \hline\end{array}$

Calculate the mean deviation (correct up to two decimal places) from the median age.

Compute mean deviation (correct up to two decimal places) from mean of the following distribution:

$\begin{array}{|llccccccc|}\hline \mathrm{Marks}& 10-20& 20-30& 30-40& 40-50& 50-60& 60-70& 70-80& 80-90\\ \mathrm{No}.\mathrm{of}students& 8& 10& 15& 25& 20& 18& 9& 5\\ \hline\end{array}$

Compute the mean deviation from the median of the following distribution:

$\begin{array}{|llllll|}\hline \mathrm{Class}& 0-10& 10-20& 20-30& 30-40& 40-50\\ \mathrm{Frequency}& 5& 10& 20& 5& 10\\ \hline\end{array}$

Find the mean deviation from the median for the following data:

$\begin{array}{|llllll|}\hline \mathrm{Mark} \mathrm{obtained}& 10& 11& 12& 14& 15\\ \mathrm{No}. \mathrm{students}& 2& 3& 8& 3& 4\\ \hline\end{array}$

Find the mean deviation from the median for the following data:

$\begin{array}{|ccccccc|}\hline x_i& 74& 89& 42& 54& 91& 94 35\\ f_i& 20& 12& 2& 4& 5& 3 4\\ \hline\end{array}$

Find the mean deviation (in decimal form) from the mean for the following data:

Find the mean deviation from the mean for the following data:

Calculate the mean deviation from the mean for the following data: $57,64,43,67,49,59,44,47,61,59$

Calculate the mean deviation from the mean for the following data:

$36, 72, 46, 42, 60, 45, 53, 46, 51, 49$.

Calculate the mean deviation from the mean for the following data:

$38, 70, 48, 40, 42, 55, 63, 46, 54, 44$.

Calculate the mean deviation from the mean for the following data:

$13, 17, 16, 14, 11, 13,10, 16, 11, 18, 12, 17$

Calculate the mean deviation from the mean for the following data:

$4, 7, 8, 9, 10, 12, 13, 17$.

Calculate the mean deviation about the median of the following observations:

$38, 70, 48, 34, 63, 42, 55, 44, 53, 47$.

Calculate the mean deviation about the median of the following observations:

$22, 24, 30, 27, 29, 31, 25, 28, 41, 42$

Calculate the mean deviation about the median of the following observations:

$34, 66, 30, 38, 44, 50, 40, 60, 42, 51$

If the sum of the squares of deviations for $10$ observations taken from their mean is $2.5$, then write the value of standard deviation. (write the answer in decimal form)