Equilibrium

A force of $120 \mathrm{N}$ and a force of $20 \mathrm{N}$ acting simultaneously at a point may produce a resultant force of

A body of mass $\mathrm{M}$ is kept on a rough horizontal surface (friction coefficient $\mu$). A person is trying to pull the body by applying a horizontal force but the body is not moving. The force by the surface on the body is $\mathrm{F},$ where

A $7 \mathrm{kg}$ object is subjected to two forces ${\overrightarrow{F}}_1=\left(20\hat{\mathrm{i}}+30\hat{\mathrm{j}}\right)$ and ${\overrightarrow{F}}_2=\left(8\hat{\mathrm{i}}+5\hat{\mathrm{j}}\right) \mathrm{N}$. The magnitude of resulting acceleration in $\mathrm{m} {\mathrm{s}}^{-2}$ will be

Find the magnitude of the resultant of shown forces in $XY$ plane.

A ball of mass $0.2 \mathrm{kg}$ is thrown vertically upwards by applying a constant force by hand. If the hand moves $0.2 \mathrm{m}$ while applying the force and the ball goes upto $2 \mathrm{m}$ height further, find the magnitude of the force. Consider $g=10 \mathrm{m} {\mathrm{s}}^{-2}$.

A balloon of gross weight $w$ Newton is falling vertically downward with a constant acceleration $a(<g)$. The magnitude of the air resistance is (Neglecting buoyant force)

A body of mass $M$ is acted upon by a force $F$ and the acceleration produced is $a$. If three coplanar forces each equal to $F$ and inclined to each other at $120°$ act on the same body and no other forces are acting. The acceleration produced will be:

A body is moving under the action of two forces $\overrightarrow{F_1}=2\hat{i}-5\hat{\mathit{j}}; \overrightarrow{F_2}=3\hat{i}-4\hat{j}$. For its velocity to become uniform a third force $\overrightarrow{F_3}$ acts on it, then this force $\overrightarrow{F_3}$ can be given by:

The sum of the magnitudes of two forces acting at a point is $16 \mathrm{N}$. The resultant of these forces is perpendicular to the smaller force and has a magnitude of $8 \mathrm{N}$. If the smaller force is of magnitude $x$, then the value of $x$ is,

The engine of a car produces an acceleration of $6 \mathrm{m} {\mathrm{s}}^{-2}$ in the car. If this car pulls another car of the same mass, then the acceleration would be,

A body is under the action of two mutually perpendicular forces of 3 N and 4 N. The resultant force acting on the body is

The sum of the magnitudes of two forces acting at a point is $18 \mathrm{N}$ and the magnitude of their resultant is $12 \mathrm{N}$. If the resultant is at $90°$ with the smaller force, the magnitude of the forces in $\mathrm{N}$ are

A boy is hanging from a horizontal branch of a tree. The tension in the arms will be maximum when the angle between the arms is

Two forces $\overrightarrow{{\text{F}}_1}$ and $\overrightarrow{{\text{F}}_2}$  are acting at right angles to each other. Then their resultant is

The resultant of two forces, each $P$, acting at an angle θ is

Two forces, each equal to $F$, act as shown in figure. Their resultant is

A body of mass $2 \mathrm{kg}$ is acted upon by two perpendicular forces $4 \mathrm{N}$ and $3 \mathrm{N}.$ The magnitude and direction of the acceleration of the body respectively are:

A force is inclined at $60°$ to the horizontal. If its component in the horizontal direction is $50 \mathrm{N},$ then magnitude of the vertical component of force is approximately:

A force is inclined at $60°$ to the horizontal. If its rectangular component in the horizontal direction is $50 \mathrm{N}$, then magnitude of the force in the vertical direction is

A man, using a 70 kg garden roller on a level surface exerts a force of 200 N at 45$°$ to the ground. What is the vertical force of the roller on the ground, if he pushed the roller? ($\mathrm{g}=10\mathrm{m}{\mathrm{s}}^{-2}$)