Incircle and Excircle of a Triangle

The value of $\frac{1}{bc}+\frac{1}{ca}+\frac{1}{ab}$ is equal to: $\{$where $a,b,c$ denote $3$ sides of a $\Delta ABC$ and $r$ is a in-radius of $\Delta ABC$ and $R$is a circum-radius of $\Delta ABC\}$

$\frac{1}{{\text{r}}^2}+\frac{1}{{\text{r}}_1^2}+\frac{1}{{\text{r}}_2^2}+\frac{1}{{\text{r}}_3^2}=$

$a·cotA+b·cotB+c·\cot C=$

In a triangle  $ABC,a:b:c=4:5:6.$ The ratio of the radius of the circumcircle to that of the incircle is: $\{ \mathrm{where} a=BC, b=CA, c=AB\}$

In triangle $ABC$, if $BC$ is the hypotenuse, then $r_2+r_3=$

Let $A$ be the area of in-circle and $A_1,A_2,A_3$ be the areas of ex-circles of a triangle. If $A_1=4,A_2=9,A_3=16$, then $A=$

Mention the formulae to find the in-radius (Apothem) of a regular polygon, when its (a) side length is given (b) circum-radius is given

Prove that in any $\Delta ABC, R+r\ge \min \left({\ell }_a,{\ell }_b,{\ell }_c\right)$, where $R$ is the circumradius, $r$ the inradius, and ${\ell }_a,{\ell }_b,{\ell }_c$ the angle bisectors of the triangle.

Let $ABC$ be triangle with $AB=AC=6$. If the circum radius of the triangle is $5$, then $BC$ equals

If $R$ is the circum radius of $\Delta ABC$ , then $A\left(\Delta ABC\right)$ = ….

The value of $\frac{1}{bc}+\frac{1}{ca}+\frac{1}{ab}$ is equal to: $\{$where $a,b,c$ denote $3$ sides of a $\Delta ABC$ and $r$ is a in-radius of $\Delta ABC$ and $R$is a circum-radius of $\Delta ABC\}$

In $\text{Δ}\text{ABC}$ , BC = 13 cm, AC = 14 cm and AB = 15 cm, then its circum-radius is equal to

$AD, BE, CF$ are internal angular bisectors of $∆ABC$ and $I$ is the incentre. If $a(b+c)\sec \frac{A}{2}ID+b(a+c)\sec \frac{B}{2}IE+c(a+b)\sec \frac{C}{2}IF=kabc,$ then the value of $k$ is:

Let $H$ be the orthocentre of triangle $ABC.$ Then the angle subtended by side $BC$ at the centre of incircle of $∆CHB$ is:

$$  ΔABC   r is inradius and r₁, r₂, r₃ are exradii opposite to vertex A, vertex B and , vertex C respectively
If r₁ = 8, r₂ = 12, r₃ = 24, then r is equal to 

In a triangle $\left(1-\frac{r_1}{r_2}\right)\left(1-\frac{r_1}{r_3}\right)=2$, then the triangle is ( r₁, r₂ and r₃ are exradii of traingle)

In any $∆ABC,$ the line joining the circumcentre $\left(O\right)$ and incentre $\left(I\right)$ is parallel to $AC,$ then $OI$ is equal to-

Find the area of the circumcircle of $∆ABC$, if $b=2, \angle B=30°$.

In a triangle, if $r_1 > r_{2 }> r_3$.Tick the appropriate option.

Let $a, b,$ and $c$ be the side lengths of a triangle $ABC$ and assume that $a\le b$ and $a\le c.$ If $x=\frac{b+c-a}{2},$ then find the minimum value of $\frac{ax}{rR},$ where $r$ and $R$ denote inradius and circumradius of triangle $ABC.$