Resonance in Series LCR Circuit

An $\mathrm{LCR}$ circuit is connected to an $\mathrm{AC}$ source. At resonance, the phase difference between the applied voltage and the current flowing in the circuit will be

In a series$L C R$  circuit the resistance $R$ was replaced by $\frac{R}{2}$$.$ Which of the following statements is CORRECT?

A circuit consisting of a resistor$\left(R\right)$, inductor$\left(L\right)$ and capacitor$\left(C\right)$ is connected to an alternating voltage source. At resonance the impedance of the circuit will be

A series LCR circuit has a capacitor $6.25 \mu \mathrm{F}$ in series with a resistance $R=300 \mathrm{\Omega }$ and an inductance $L.$ The circuit is driven by a voltage $V=240 \cos \left(400t\right).$

If the circuit is in resonance, the magnitude of the voltage drop across the R-L segment (i.e. drop across the points $P$ and $Q$ ) is

In the following circuit the readings of AC voltmeters and ammeters will be respectively-

Half power point frequencies for which the power in the circuit is half of the ___________________ power in the circuit.

The inductance of the oscillatory circuit of the radio station is $10 \mathrm{mH}$ and its capacitance is $0.25 \mathrm{\mu F}$. Taking the effect of resistance negligible, wavelength of the broadcasted waves will be (velocity of light $=3.0\times {10}^8 \mathrm{m} {\mathrm{s}}^{-1},\mathrm{ }\mathrm{\pi }=3.14$)

In LCR series circuit $L=4H, C=36 \mu F \mathrm{and} R=16\Omega$, then bandwidth of resonance is 

The bandwidth of resonance in the $L-C-R$  A.C. circuit is proportional to inductance.

The inductance of the oscillatory circuit of the radio station is $10 \mathrm{mH}$ and its capacitance is $0.25 \mathrm{\mu F}$. Taking the effect of resistance negligible, wavelength of the broadcasted waves will be (velocity of light $=3.0\times {10}^8 \mathrm{m} {\mathrm{s}}^{-1},\mathrm{ }\mathrm{\pi }=3.14$)

Which one is the expression of resonant frequency in a series resonant circuit?

A parallel L-C circuit comprises of a 5H inductor and $5\mathrm{\mu F}$ capacitor. The resonant frequency of the circuit in $\mathrm{Hz}$ is 

In the given figure, which point shows the resonant state?

In a series resonant circuit, having $\mathrm{L}, \mathrm{C}$ and $\mathrm{R}$as its elements, the resonant current is $i$. The power dissipated in the circuit at resonance is

The given figure represents the phasor diagram of a series $\mathrm{LCR}$ circuit connected to an ac source. At the instant $t\text{'}$t' when the source voltage is given by $V=V_0\cos \left(\omega t^{\text{'}}\right)$, the current in the circuit will be :

In the $RLC$ circuit in the figure, $R=60 \Omega ,$ $L=3 \mathrm{mH}, C=4 \mathrm{mF},$ and the source of time varying emf has a peak voltage of $120 \mathrm{V}.$ What should the angular frequency of the source, $\omega$, be to produce the largest current in the resistor?

If value of $R$ is changed, then :-

The resonance frequency of the tank circuit of an oscillator when $L=\frac{10}{{\pi }^2} \mathrm{mH}$ and $C=0.04 \text{μF}$ are connected in parallel is

In a series resonant circuit, the AC voltage across resistance $R$, inductor $L$ and capacitor $C$ are $5 \mathrm{V}, 10 \mathrm{V} \mathrm{and} 10 \mathrm{V}$, respectively. The AC voltage applied to the current will be

In $LCR$ series circuit, the resonance condition in terms of capacitive reactance $\left(X_C\right)$ and inductive reactance $\left(X_L\right)$ is