Energy Stored in a Capacitor

When a dielectric of dielectric constant $\mathrm{K}$ is placed in between the plates of the parallel plate condenser while it is connected with the source of potential, then

A parallel plate capacitor is charged by a battery and the battery remains connected, a dielectric slab is inserted in the space between the plates. Explain what changes if any, occur in the values of the electric field between the plates and the energy stored in the capacitor.

A parallel plate capacitor is charged by a battery and the battery remains connected, a dielectric slab is inserted in the space between the plates. Explain what changes if any, occur in the values of the capacity of the capacitor.
 

A parallel capacitor is charged by a battery. The battery is disconnected, and a dielectric slab (K is the dielectric constant of the slab) is inserted to completely fill the space between the plates then its capacitance increase by

A parallel capacitor is charged by a battery. The battery is disconnected, and a dielectric slab is inserted to completely fill the space between the plates because of this process electric field decrease.this statement is ture or false.

A parallel capacitor is charged by a battery. The battery is disconnected, and a dielectric slab is inserted to completely fill the space between the plates. How will,
Its capacitance is affected.

The maximum charge stored on a metal sphere of radius $15 \mathrm{cm}$ may be $7.5 \mathrm{\mu C}$. The potential energy of the sphere in this case is

The capacity of a capacitor is $4\times {10}^{-6} \mathrm{F}$ and its potential is $100 \mathrm{V}$. The energy released on discharging it fully will be

A parallel plate capacitor having a plate separation of $2 \mathrm{mm}$ is charged by connecting it to a $300 \mathrm{V}$ supply. The energy density is

The potential difference between the plates of a parallel plate capacitor is $10 V$ and separation is $5 \mathrm{cm}\mathit{.}$ Find the energy density between plates. $\left({\epsilon }_0={10}^{-11} \mathrm{F} {\mathrm{m}}^{-1}\right)$

A.DC circuit consisting of two cells of emf $V$ and $2V$ having no internal resistance are connected with two capacitors of capacity $C$ and $2C$ and four resistors $R, R, 2R$and $2R$ as shown in figure. The ammeter and voltmeter used in the circuit are ideal.

In steady state, the energy stored by the capacitor $\mathrm{C}$ is

A $16\mathrm{ }\mathrm{p}\mathrm{F}$ capacitor is connected to $70\mathrm{ }\mathrm{V}$ supply. The amount of electric energy stored in the capacitor is

When a potential difference of $100$ volts is applied between the parallel plates of a capacitor whose capacitance is $5\times {10}^{-6}\mathrm{ }\mathrm{F},$ then the energy stored as electrostatic potential energy in the capacitor is

The energy of a parallel plate capacitor when connected to a battery is $E$. With the battery still in connection, if the plates of the capacitor are separated so that the distance between them is twice the original distance, then the electrostatic energy becomes.

Two capacitors of capacitance $2\mu F$ and $4\mu F$ respectively are connected in series. The combination is connected across a potential difference of 10V. The ratio of energies stored by capacitors will be ........

The energy of a charged capacitor is u. Another identical capacitor is connected parallel to the first capacitor, after disconnecting the battery. The total energy of the system of these capacitors will be ............

If there are $n$ capacitors in parallel connected to $V$ volt source, then the energy stored is equal to

A capacitor is charged until its stored energy is $3\mathrm{ }\mathrm{J}$ and the charging battery is removed. Now another uncharged capacitor is connected across it and it is found that charge distributes equally. The final value of total energy stored in the electric fields is

The dimension of $\left(\frac{1}{2}\right){\mathrm{\epsilon }}_0{\mathrm{E}}^2$ (${\mathrm{\epsilon }}_0\mathrm{ }:\mathrm{ }\mathrm{p}\mathrm{e}\mathrm{r}\mathrm{m}\mathrm{i}\mathrm{t}\mathrm{t}\mathrm{i}\mathrm{v}\mathrm{i}\mathrm{t}\mathrm{y}\mathrm{ }\mathrm{o}\mathrm{f}\mathrm{ }\mathrm{f}\mathrm{r}\mathrm{e}\mathrm{e}\mathrm{ }\mathrm{s}\mathrm{p}\mathrm{a}\mathrm{c}\mathrm{e}$ ; $\mathrm{E}\mathrm{ }:\mathrm{ }\mathrm{e}\mathrm{l}\mathrm{e}\mathrm{c}\mathrm{t}\mathrm{r}\mathrm{i}\mathrm{c}\mathrm{ }\mathrm{f}\mathrm{i}\mathrm{e}\mathrm{l}\mathrm{d})$ is 

The average value of electric energy density in an Electromagnetic Waves is (E0 is peak value)