Energy Density in Magnetic Field

A long solenoid with 40 turns per cm carries a current of 1A. The magnetic energy stored per unit volume is _____$\raisebox{1ex}{$\mathrm{\pi } J$}\!\left/ \!\raisebox{-1ex}{$m^3$}\right.$
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A current of 2A flows through a solenoid of self-inductance of 3 mH. the energy stored in the solenoid will be-

A solenoid of inductance 2H carries a current of 1A. What is the magnetic energy stored in a solenoid?
 

The expression for the energy density in the magnetic field is given by,

$u=\frac{1}{2}\frac{B^2}{{\mu }_0}$

Where, the value of ${\mu }_0$ is $8.85\times {10}^{-12} \mathrm{F}/\mathrm{m}$.

The magnetic field stored per unit volume is $\mathrm{nBH} \mathrm{J}/{\mathrm{m}}^3$. Here the value of $n$ is ?

Write the energy density formula in the case of a magnetic field or inductor.

The work done by emf in solenoid is the product of _____ and volume of the solenoid.

The self inductance of a given solenoid is $500 \mathrm{mH}$. Calculate the energy stored in the solenoid if $100 \mathrm{mA}$ of current is flowing through it.

The magnetic energy density of a solenoid is independent of magnetic permeability in vacuum.

The magnetic energy per unit volume is

For a solenoid derive the magnetic energy stored in it, in terms of magnetic field, area of cross-section and it's length.

Magnetic energy stored in the solenoid in the terms of magnetic field $B$, area $A$ and length $L$ of the solenoid.

Cotyledons are also called-