Torque on Current Loop, Magnetic Dipole

The figure shows a  current-carrying square loop $ABCD$ of side $10 \mathrm{cm}$ and current $i=10 \mathrm{A}$. The magnetic moment $\overrightarrow{M}$ of the loop is

A rectangular coil PQ has $2n$ turns, an area $2a$ and carries a current $2I$, (refer figure). The plane of the coil is at $60^{\text{o}}$ to a horizontal uniform magnetic field of flux density $B$. The torque on the coil due to magnetic force is

A conducting ring of mass $2 \mathrm{kg}$ and radius $0.5 \mathrm{m}$ is placed on a smooth horizontal plane. The ring carries a current $i=4 \mathrm{A}$. A horizontal magnetic field $B=10 \mathrm{T}$ is switched on at time $t=0$ as shown in the figure. The initial angular acceleration of the ring will be

A wire loop carrying current $i$ is placed in the $x-y$ plane as shown in the figure. If an external uniform magnetic field $\overrightarrow{B}=B\hat{\text{i}}$ is switched on, then the torque acting on the loop is

The magnetic moment of the current carrying loop shown in the figure is equal to

As shown below, a magnetic dipole moment is oriented in 3 different ways in a uniform magnetic field.

Which orientation has the largest potential energy?

As shown below, a magnetic dipole moment is oriented in 3 different ways in a uniform magnetic field.

Which orientation results in the largest magnetic torque on the dipole?

In case of dipole in a uniform magnetic field, when we write for equilibrium condition, negative sign is considered when determine the torque. Why?

A magnet of length $10 \mathrm{cm}$ and pole strength $0.5 \mathrm{A}·\mathrm{m}$ is placed normal to a uniform magnetic field of strength $5\times {10}^{-5} \mathrm{Wb}·{\mathrm{m}}^{-2}$. Calculate the moment of the couple acting on it.

A uniform rigid square wire frame of side length $l$ and mass $4m$ is placed on a smooth horizontal surface where exists a uniform horizontal magnetic field of Intensity $B$. Now current that is double of minimum current required to flip over the frame is switched on in the coil. Then just after current is switched on

A steel wire of length $l$ and magnetic moment $M$ is bent into a semicircular arc of radius $R$. The new magnetic moment is

A bar magnet suspended by a horse hair lies in the magnetic meridian when there is no twist in the hair, On turning the upper end of the hair through $150°$ from the meridian the magnet is deflected through $30°$ form the meridian. Then the angle through which the upper end of the hair has to be twisted to deflect the magnet through $90°$ from the meridian is ,

A bar magnet of length $10 \mathrm{cm}$ and pole strength $20 \mathrm{A}-\mathrm{m}$ is deflected through $30°$ from the magnetic meridian. If earth's horizontal component field is $\frac{320}{4\pi }\mathrm{A} {\mathrm{m}}^{-1}$. The moment of the deflecting couple is

A square loop of side $l$ is kept in a uniform magnetic field $B$ such that its plane makes an angle with $\overrightarrow{B}$. The loop carries a current $i$. The torque experienced by the loop in this position is

A rectangular loop consists of $N$ closed wrapped turns and has dimensions $a\times b$. The loop is hinged along the Y-axis. What is the magnitude of the torque exerted on the loop by a uniform magnetic field $B=B_0$ direction shown. The torque acting on the loop is

A wire loop $ABCDEA$ carrying a current $I$ is placed in $X-Y$ plane as shown. The external magnetic field $\overrightarrow{B}=B_x\hat{i}+B_z\hat{k}$ is applied in the region(here $B_{\mathrm{x}}$ and $B_{\mathrm{z}}$ are constant). Then if torque acting on the loop is $\frac{i{r}^2}{k}\left(\pi -1\right)B_x$ find $k$.

The magnetic dipole moment of a current loop does not depend on magnetic field present around current carrying loop.

A nonconducting sphere has mass $8.0\mathrm{kg}$ and radius $0.2 \mathrm{m}$. A flat compact coil of wire with $50$ turns is wrapped tightly around it, with each turn concentric with the sphere. As shown in the figure, the sphere is placed on an inclined plane that slopes downward to the left, making an angle $\theta$ with the horizontal, so that the coil is parallel to the inclined plane. A uniform magnetic field of $0.35 \mathrm{T}$ vertically upward exists in the region of the sphere. If the sphere rests in equilibrium on the inclined plane, the current through the coil is closest to

The direction of magnetic dipole moment is from North pole to South pole.

What is the direction of magnetic dipole moment?