Poisson’s Ratio

A material has Poisson’s ratio $0.2$. If a uniform rod made out of it suffers longitudinal strain $4.0\times {10}^{–3}$, then calculate the percentage change in its volume.

A material has Poisson’s ratio $0.2$. If a uniform rod made out of it suffers longitudinal strain $4.0\times {10}^{–3}$, then calculate the percentage change in its volume.

The increase in length on stretching a wire is $0.05\%$. If it's Poisson's ratio is $0.4,$ then its diameter:

For a given material, the Young’s modulus is $2.4$ times that of the modulus of rigidity. Its Poisson’s ratio is:

If a force is applied to an elastic wire of the material of Poisson's ratio $0.2$ there is a decrease of the cross-sectional area by $1\mathrm{\%}$. The percentage increase in its length is:

A material has Poisson’s ratio $0.2$. If a uniform rod made out of it suffers longitudinal strain $4.0\times {10}^{–3}$, then calculate the percentage change in its volume.

If the volume of the wire remains constant when it is subjected to tensile stress, the value of Poisson’s ratio of the material of the wire is

The ratio of lateral strain to the longitudinal strain is called

A copper wire of cross-section A is under tension T. Find the fractional decrease in the cross-sectional area (Young's modulus is $Y$ and Poisson's ratio is $\sigma$ )

Given the following values for an elastic material Young's modulus $=\mathrm{ }7\mathrm{ }\times \mathrm{ }{10}^{10}\mathrm{ }\mathrm{N}{\mathrm{m}}^{-2}$ and Bulk modulus $=\mathrm{ }11\mathrm{ }\times \mathrm{ }{10}^{10}\mathrm{ }\mathrm{N}{\mathrm{m}}^{-2}$. The Poisson's ratio of the material is -

Given the following values for an elastic material Young's $\mathrm{m}\mathrm{o}\mathrm{d}\mathrm{u}\mathrm{l}\mathrm{u}\mathrm{s}=7\mathrm{ }\times \mathrm{ }{10}^{10}\mathrm{ }{\mathrm{N}\mathrm{m}}^{–2}$ and Bulk $\mathrm{m}\mathrm{o}\mathrm{d}\mathrm{u}\mathrm{l}\mathrm{u}\mathrm{s}=11\mathrm{ }\times \mathrm{ }{10}^{10}\mathrm{ }{\mathrm{N}\mathrm{m}}^{–2}$. The Poisson's ratio of the material is -

If there is no change in the volume of wire on stretching, then Poisson's ratio for the material of wire is -

Given the following values for an elastic material: Young's $\mathrm{m}\mathrm{o}\mathrm{d}\mathrm{u}\mathrm{l}\mathrm{u}\mathrm{s}=7\times {10}^{10}\mathrm{ }{\mathrm{N}\mathrm{m}}^{-2}$ and $\mathrm{B}\mathrm{u}\mathrm{l}\mathrm{k}\mathrm{ }\mathrm{m}\mathrm{o}\mathrm{d}\mathrm{u}\mathrm{l}\mathrm{u}\mathrm{s}=11\times {10}^{10}\mathrm{ }{\mathrm{N}\mathrm{m}}^{-2}$. The Poisson's ratio of the material is -

The increase in length on stretching a wire is 0.05%. If its Poisson's ratio is 0.4, the diameter is reduced by

There is no change in the volume of a wire due to change in its length on stretching. The Poisson's ratio of the material of wire is

The Poisson's ratio cannot have the value

When a wire of length $10 \mathrm{m}$ is subjected to a force of $100 \mathrm{N}$ along its length, the lateral strain produced is $0.01\times {10}^{-3} \mathrm{m}$. The Poisson's ratio was found to be $0.4$. If the area of cross-section of wire is $0.025\mathrm{ }{\mathrm{m}}^2$, its Young's modulus is

When a wire of length $10 \mathrm{m}$ is subjected to a force of $100 \mathrm{N}$ along its length, the lateral strain produced is $0.01\times {10}^{-3} \mathrm{m}$. The Poisson's ratio was found to be $0.4$. If the area of cross-section of wire is $0.025\mathrm{ }{\mathrm{m}}^2$, its Young's modulus is

Which of the following relation is true?

When a rubber cord is stretched, the change in volume with respect to change in its linear dimensions is negligible. The Poisson's ratio for rubber is