Alpha Scattering

In Rutherford's experiment, a thin gold foil was bombarded by alpha particles. If Thomson's "Plum Pudding Model" of the atom were correct, what would have been the outcome of the experiment?

In Rutherford scattering experiment, the correct angle of scattering of α− particles for impact parameter equal to zero is

In Rutherford's experiment, the alpha particles that come closer to the nuclei are

Out of the following statements regarding Rutherford's model, which of the following is/are correct?

a. Most of the space inside an atom is empty.

b. The electrons revolve around the nucleus under the influence of coulomb force acting on them.

c. Most part of the mass of the atom and its positive charge are concentrated at its centre.

d. The stability of atom was established by the model.

Assertion (A): The impact parameter for scattering of $\alpha$ - particles by $180°$ is zero.
Reason (R): Zero impact parameter means that the $\alpha$-particles tend to hit the center of the nucleus.

Geiger-Marsden experiment is related with the size of the-

In Rutherford's experiment, an $\text{α}$-particle of mass $m$ and charge $q$ moves at high speed $u$, along the $x$-axis. It is initially near $x=-\infty$, and it ends up near $x=+\infty .$ The gold nucleus having charge $Q$ is fixed at the point $x=0, y=-d$. As the $\text{α}$-particle passes the stationary nucleus, its $x$-component of velocity does not change appreciably, but it acquires a small velocity in the $y$-direction. The angle through which the $\text{α}$-particle is deflected is,

On which of the following factors does the trajectory of an alpha particle depend?

The significant result deduced from the Rutherford's scattering experiment is that

What is the conclusion of Rutherford’s alpha particle scattering experiment ?

$\alpha$-particles of $\text{6 MeV}$ energy are scattered back from a silver foil. If the maximum volume in which the entire positive charge of the atom is supposed to be concentrated is $4.8\times {10}^{-\mathrm{n}} {\mathrm{m}}^3$ then find value of n. $\left[\left(\text{Z for Ag}=\text{47}\right)\text{,}\mathrm{ k}=\text{9.0}\times {\text{10}}^9{\text{ Nm}}^2{\text{ C}}^{-2}\right]$.

An $\alpha -$ particle after passing through a potential difference of $V$ volts collides with a nucleus. If the atomic number of the nucleus is $Z$ then the distance of closest approach of $\alpha -$ particle to the nucleus will be

According to $\mathrm{\alpha }-$particle scattering experiment of Rutherford.
$\mathrm{N}\left(\mathrm{\theta }\right) \propto$ $\frac{1}{\mathrm{K}.{\mathrm{E}}^{\mathrm{x}}}$
Here $\mathrm{N}\left(\mathrm{\theta }\right) =$ no. of α-particle scattered at an angle $\mathrm{\theta }.$
$\mathrm{K}.\mathrm{E} =$Kinetic energy (initial) of $\mathrm{\alpha }-$particle.
What is the value of $\mathrm{x} ?$

The distance of closest approach of an $\alpha$ particle fired towards a nucleus with momentum $p$ is $r$. If the momentum of the $\alpha$ particle is $2p$, the corresponding distance of closest approach is

Particle used in the Rutherford's scattering experiment to deduce the structure of atoms

Which of the following is incorrect regarding Rutherford's atomic model?

The distance of closest approach of an $\mathrm{\alpha }$ -particle fired towards a nucleus with momentum $p$, is $r$. What will the distance of closest approach when the momentum of $\mathrm{\alpha }$ -particle is $2p$?

The specific charge of a proton is $9.6\times {10}^7 \mathrm{C}\mathrm{k}{\mathrm{g}}^{-1}$. The specific charge of an alpha particle will be,

An alpha nucleus of energy $\frac{1}{2}m{v}^2$ bombards a heavy nuclear target of charge $Ze$. Then the distance of closest approach for the alpha nucleus will be proportional to

In Wilson cloud chamber experiment, two particles were found to show equal deviation but in opposite directions. The names positron and negatron were given to these particles by Andersson. Negatron should be