Mass-energy and Nuclear Binding Energy

The plot of the binding energy per nucleon versus the mass number A for a large number of nuclei,  $2\le A\le 240$  is shown in Fig. In which range the binding energy per nucleon is constant?

The plot of the binding energy per nucleon versus the mass number A for a large number of nuclei,  $2\le A\le 240$  is shown in Fig. In which range the binding energy per nucleon is constant?

Calculate the energy released in MeV in the following nuclear reaction :<

${}_{92}^{238}\text{U}\to {}_{90}^{234}\text{Th}+{}_2^4\text{He}+\text{Q}$

[Mass of  ${}_{92}^{238}\text{U}$ = 238.05079 u]

Mass of  ${}_{90}^{234}\text{Th}$ = 234.043630 u

Mass of  ${}_2^4\text{He}$  = 4.002600 u

1 u = 931.5 MeV

$\text{Mass of neutron}=1.008665 \mathrm{u}$

In the nuclear process, ${{}_{6}C}^{11}\to {{}_{5}B}^{11}+{\beta }^{+}+X, X$ stands for _______

Binding energy of a nucleus is,

The binding energy per nucleon is maximum in the case of,

If an $\mathrm{H}$-nucleus is completely converted into energy, the energy produced will be around

Define:

Binding energy of electron

Calculate binding energy for ${}_{26}{}^{56}\mathrm{Fe}$ nucleus. [Given, atomic mass of ${}_{26}{}^{\text{56 }}\mathrm{Fe}=55.9349 \mathrm{u}$, mass of neutron $=1.00867 \mathrm{u}$, mass of proton $=1.00783 \mathrm{u}$ and $\mathrm{u}=931 \mathrm{MeV}/{\mathrm{c}}^2$]

Explain mass effect and binding energy? Explain the main conclusions which can be drawn from the binding energy per nucleon versus mass number diagram.

Which of the following nucleus having highest binding energy per nucleon:

The average binding energy per nucleon(in $\mathrm{MeV}$) of ${}_{41}{}^{93}\mathrm{N}\mathrm{b}$ having mass $92.906376 \mathrm{u}$ is $n$. Write the value of $\left[n\right]$, where $\left[\right]$ denotes the greatest integer function.

(Given $m_p=1.0072796 \mathrm{u}$, $m_n=1.008665 \mathrm{u}$ and $1 \mathrm{u}=931 \mathrm{MeV}/c^2$ )

Let $m_p$ be the mass of proton, $m_n$ the mass of a neutron, $M_1$ the mass of a ${}_{10}{}^{20}\mathrm{N}\mathrm{e}$ nucleus, and $M_2$ the mass of a ${}_{20}{}^{40}\mathrm{C}\mathrm{a}$ nucleus. Then,

Mass defect $\mathrm{\Delta }M$ is always

Energy in electron volt corresponding to Compton wavelength $0.0242 \mathrm{Å}$ is

The mass defect in a particular nuclear reaction is $0.3 \mathrm{g}.$ The amount of energy liberated in kilowatt hour is (velocity of light $=3\times {10}^{\mathrm{8 }}\mathrm{m}/\mathrm{s}$)

The binding energy per nucleon is maximum in the case of

$N{e}_{ 10}^{ 20}\to { }_{2}H{e}^4+ { }_{2}H{e}^4+{ }_6{C}^{12}$

If binding energy per nucleon of $N{e}_{ 10}^{ 20}$ is $8.03\mathrm{ }\mathrm{MeV}$, ${ }_2{He}^4$ is $7.07\mathrm{ }\mathrm{MeV}$ and ${ }_6{C}^{12}$ is $7.86\mathrm{ }\mathrm{MeV}$, then what is $Q\left(\text{in} \mathrm{MeV}\right)$ value of the reaction

A nucleus ${}_Z{}^{A}X$ has mass represented by $m\left(A, Z\right)$ . If $m_p$ and $m_n$ denote the mass of proton and neutron respectively and $BE$ the binding energy (in MeV) then,