Thermionic Emission and Cathode Ray Tube

Figure shows a radioactive source $S$ in a thick lead walled container having a narrow opening. The radiations pass through an electric field between the plates $A$ and $B.$

Why is the source $S$ kept in a thick lead walled container with a narrow opening ?

Figure shows a radioactive source $S$ in a thick lead walled container having a narrow opening. The radiations pass through an electric field between the plates $A$ and $B.$

Complete the diagram to show the paths of $\alpha ,\beta$ and $\gamma$ radiations.

The diagram in Figure shows a radioactive source $S$placed in a thick lead walled container. The radiations given out are allowed to pass through a magnetic field. The magnetic field (shown as $x$ ) acts perpendicular to the plane of paper inwards. Arrows show the paths of the radiations $A,B$ and $C.$

Explain clearly how you used the diagram to arrive at the answer.

The diagram in Figure shows a radioactive source $S$placed in a thick lead walled container. The radiations given out are allowed to pass through a magnetic field. The magnetic field (shown as $x$ ) acts perpendicular to the plane of paper inwards. Arrows show the paths of the radiations $A,B$ and $C.$

Name the radiations labelled $A, B$ and $C.$

Figure shows a mixed source $R$ of alpha and beta particles in a thick lead walled container. The particles pass through a magnetic field in a direction perpendicular to the plane of paper inwards as shown by $x.$ (a) Show in the diagram how the particles get affected.
[Hint : Alpha particles will deflect to the left while beta particles to the right]

Figure shows a mixed source $R$ of alpha and beta particles in a thick lead walled container. The particles pass through a magnetic field in a direction perpendicular to the plane of paper inwards as shown by $x.$ (a) Show in the diagram how the particles get affected. (b) Name the law used in part (a).
[Hint : Alpha particles will deflect to the left while beta particles to the right]

A certain nucleus $A$ (mass number $238$ and atomic number $92$) is radioactive and becomes a nucleus $,B$ (mass number $234$ and atomic number $90$ ) by the loss of a particle.
 Explain how you arrived at your answer.

What is the mass number of the nucleus $A$ ?

A certain nucleus $A$ (mass number $238$ and atomic number $92$) is radioactive and becomes a nucleus $,B$ (mass number $234$ and atomic number $90$ ) by the loss of a particle.
State the change in the form of a reaction.

Does the composition of nucleus $C$ change if it emits a $\gamma$-radiation ?

A certain nucleus $A$ (mass number $238$ and atomic number $92$) is radioactive and becomes a nucleus $,B$ (mass number $234$ and atomic number $90$ ) by the loss of a particle.

What particle was emitted ?

The nucleus $B$ emits a $\beta$-particle and is transformed into a nucleus $C.$ What is the composition of $C$ ?

An atomic nucleus $A$ is composed of $84$ protons and $128$ neutrons. The nucleus $A$ emits an $\alpha$-particle and is transformed into a nucleus $\mathrm{B}$. What is the composition of $B$ ?

An element $\mathrm{P}$ disintegrates by $\alpha$-emission and the new element suffers two further disintegrations, both by $\beta$-emission, to form an element $Q$. Explain the fact that $P$ and $Q$ are the isotopes.

A nucleus of stable phosphorus has $15$ protons and $16$neutrons.

What will be the atomic number and mass number of new nucleus formed by decay of a $\beta$-particle by the radio phosphorus in part (b) ?

A nucleus of stable phosphorus has $15$ protons and $16$neutrons.

The nucleus of radio phosphorus has one neutron more than the stable nucleus. What will be its atomic number and mass number ?

A nucleus of stable phosphorus has $15$ protons and $16$neutrons.

What is its atomic number and mass number. 

A nucleus ${}_{11}{}^{24}\mathrm{Na}$ is $\beta$-radioactive.

What general name is given to the product nucleus with respect to ${}_{11}{}^{24}\mathrm{Na}?$

A nucleus ${}_{11}{}^{24}\mathrm{Na}$ is $\beta$-radioactive.

Write the equation representing $\beta$-decay.

A nucleus ${}_{11}{}^{24}\mathrm{Na}$ is $\beta$-radioactive.
What are the numbers $24$ and $11$ called ?