Refraction through a Prism

For an isosceles prism of angle $A$ and refractive index $n$, it is found that the angle of minimum deviation ${\delta }_m=A$. Which of the following options is/are correct?

A ray $OP$ of monochromatic light is incident on the face $AB$ of prism $ABCD$ near vertex $B$ at an incident angle of $60°$ (see figure). If the refractive index of the material of the prism is $\sqrt{3}$, which of the following is (are) correct?

A monochromatic light is incident at a certain angle on an equilateral triangular prism and suffers minimum deviation. If the refractive index of the material of the prism is $\sqrt{3}$, then the angle of incidence is:

A beam of light consisting of red, green and blue colours is incident on a right-angled prism. The refractive index of the material of the prism for the above red, green and blue wavelengths are $1.39, 1.44$ and $1.47$, respectively. The prism will:

Monochromatic light is incident on a glass prism of angle $A$. If the refractive index of the material of the prism is $n$, a ray incident at an angle $\theta$, on the face $AB$ would get transmitted through the face $AC$ of the prism provided.

A parallel beam of light is incident from air at an angle $\alpha$ on the side $PQ$ of a right-angled triangular prism of refractive index $n=\sqrt{2}$. Light undergoes total internal reflection at the prism at the face $PR$ when $\alpha$ has a minimum value of $45°$. The angle $\theta$ of the prism is:

The angle of incidence for a ray of light at a refracting surface of a prism is $45°$. The angle of prism is $60°$. If the ray suffers deviation through the prism, the angle of minimum deviation and refractive index of the material of the prism respectively, are:

The refracting angle of a prism is $A$ and the refractive index of its material is $\cot \left(\frac{A}{2}\right)$. The angle of minimum deviation is:

In an experiment for determination of the refractive index of a glass of a prism by $i-\delta$, plot, it was found that a ray incident at an angle $35°$, suffers minimum deviation of $40°$ and that it emerges at an angle $79°$. In that case which of the following is closest to the maximum possible value of the refractive index?

The refractive index of the material of a prism is $\sqrt{2}$ and the angle of the prism is $30°$. On of the two refracting surfaces of the prism is made a mirror inwards, by silver coating. A beam of monochromatic light entering the prism from the other face will retrace its path (after reflection from the silvered surface) if its angle of incidence on the prism is:

A thin prism of glass placed in air produces a deviation of $4°$ in a light ray. If the prism be placed in water, what would be the new deviation? $\left({}_a\mu _g=\frac{3}{2}, {}_a\mu _w=\frac{4}{3}\right)$

A thin prism of refracting angle $10°$ produces a deviation of $5°$ in a ray of light passing through it. Find the refractive index of the prism material and the velocity of light in it.

The refracting angle of a glass prism of refractive index $1.45$ is $60°$. At what angle should a light ray be incident at the first face of the prism so that it emerges at the second face just parallel to the face?

A ray of light incident at $50°$ on a $60°$ prism suffers minimum deviation. Find the angle of minimum deviation and the refractive index of the material of the prism.

A parallel beam of light is incident on a face of a $60°$ prism. By rotating the prism, the minimum angle of deviation is measured to be $40°$. Find the refractive index of the prism material. If the prism is placed in water (refractive index $1.33$), then what would be the new minimum angle of deviation?

A glass prism whose refracting angle is $72°$ and refractive index $1.66$ is kept in a liquid of refractive index $1.33$. Calculate the angle of minimum deviation for the parallel beam passing through the prism. (Given : $\sin 36°= 0.5878, \sin 47.2°=0.7336$)

The angle of a glass prism is $59.5°$. The angle of minimum deviation is $38.5°$. Without using the value of refractive index of the glass, calculate the angle of incidence for a ray of light suffering minimum deviation.

What should be the refracting angle of a prism of refractive index $1.5$, so that a light ray incident on the prism at an angle of $50°$ suffers minimum deviation?

A regular $60°$ glass prism has refractive index $\sqrt{2}$ for a given wavelength. Calculate the angle of minimum deviation ${\delta }_m$. At what angle of incidence should a monochromatic light of this wavelength fall on the face of the prism so as to get a minimum deviation? (use $\sin 30°=\frac{1}{2}$ and $\sin 45°=\frac{1}{\sqrt{2}}$).

Calculate the angle of minimum deviation for a glass prism of angle $60°$, the refractive index of glass being $1.658$. What is the corresponding angle of incidence? Given: $\sin 56°=0.829$.