Quadratic Equations

In the following questions, two-equation numbered I and II are given. You have to solve the equation and give the answer if-

$1. x > y$
$2. x \ge y$
$3. x < y$
$4. x \le y$
$5. x= y$Or the relationship cannot be established.

I.$3x^2-47x+184 = 0$
II.$2y^2-23y+66 = 0$

In the following questions, two-equation numbered I and II are given. You have to solve the equation and give the answer if-

$$\begin{gathered} 1. x > y \\ 2. x\ge y \\ 3. x < y \\ 4. x \le y \end{gathered}$$
$5. x = y$  Or the relationship cannot be established.

I. $x^2-10\sqrt{3}x+63=0$
II.$y^2-\sqrt{2}y-24=0$

In each of the following questions, two equations are given. You have to solve them and find the relation between $p$ and $q$
 

I.$6p^2+5p+1=0$

II.$20q^2+9q=-1$

In the question, two equations (I) and (II) are given. You have to solve both the equations and give the answer.

(A) If $x>y$

(B) If $x<y$

(C) If$x\ge y$

(D) If $x\le y$

(E) If $x=y$ or there is no relationship.

In the following questions, two equations numbered I and II are given. You have to solve both the equations and Give an answer If

$\left(1\right)$$x > y$

$\left(2\right) x \ge y$

$\left(3\right) x< y$

$\left(4\right) x \le y$

$\left(5\right) x = y$  Or the relationship cannot be established

I. $2x + 3y = 19$
II.$3x - 2y = 9$

In the following questions, two equations numbered I and II are given. You have to solve the equation and give the answer if-

$1. x > y$
$2. x \ge y$
$3. x < y$
$4. x \le y$
$5. x = y$  Or the relationship cannot be established.

I. $x^2-8x+16 = 0$
II.$20y^2-y-12 = 0$

In the following questions, two-equation numbered I and II are given. You have to solve the equation and give the answer if-

$$\begin{gathered} 1. x > y \\ 2. x \ge y \\ 3. x < y \\ 4. x\le y \end{gathered}$$
$5. x = y$ Or the relationship cannot be established.

I. $x^2-14x+48=0$
II.$y^2-y-30=0$

In the following question, two equations numbered I and II are given. You have to solve both the equations and Give answer If
$1.x > y$
$2.x \ge y$
$3.x < y$
$4.x \le y$
$5.x = y$ Or the relationship cannot be established.

I.$\frac{6}{\sqrt{x}} + \frac{14}{\sqrt{x}} = 10$

II.$\frac{\sqrt{y}}{2} + \frac{\sqrt{y}}{3} = \frac{5}{2}$

In each of the following questions, two equations are given. You have to solve them and find out the relation between $a$ and $b$:

I. $a^2+6a+9=0$
II. $b^2+8b+16=0$

In the following questions, two equations numbered I and II are given. You have to solve both the equations and give answer if
1) if $x>y$
2) if $x\ge y$
3) if $x<y$
4) if $x\le y$
5) if $x=y$ or the relationship cannot be established.

I.$x² – 19x + 84 = 0$
II. $y² – 25y + 156 = 0$

In the following questions two equation numbered I and II are given. You have solve the equation and give answer if-
$1$. x $>$ y
$2$. x $\ge$ y
$3$. x $<$y
$4$. x $\le$ y
$5$. x $=$ y or the relationship cannot be established.
I. $20x^2 -31x +12=0$
II. $20y^{2 }-y-12=0$

Directions: In each of these questions, two equations $\left(\mathrm{I}\right)$ and $\left(\mathrm{II}\right)$ are given. You have to solve both the equations and give the answer
A. if $x<y$
B. if $x\le y$
C. if $x=y$, or no relation can be established between $x$ and $y$.
D. if $x>y$
E. if $x\ge y$

$$\begin{gathered} \mathrm{I}. 9x^2=1 \\ \mathrm{II}. 4y^2+11y–3 = 0 \end{gathered}$$

In each of the following questions, two equations are given. You have to solve them and find the relation between $p$ and $q$?

I.$3p² + 15p = - 18$
II. $q² + 7q + 12 = 0$

In the following questions, two equations numbered I and II are given. You have to solve both the equations and give answer if
1) if $x > y$
2) if$x \ge y$
3) if $x < y$
4) if $x \le y$
5) if $x = y$ Or the relationship cannot be established.

I. $\frac{9}{\sqrt{x}} + \frac{19}{\sqrt{x}} = \sqrt{x}$
II.$y^5 - \frac{{\left(2 \times 14\right)}^{{\displaystyle \frac{11}{2}}}}{\sqrt{y}} = 0$

In the following questions two equations numbered I and II are given. You have to solve both equations and Give answer if:

i. $X-\sqrt { 225 } =\sqrt [ 3 ]{ 9261 }$
II. $Y-\sqrt { 361 } =\sqrt [ 3 ]{ 6859 }$

In the following question, two equations numbered I and II are given. You have to solve both the equations and give answer if

$\left(1\right) x > y$
$\left(2\right) x > y or x = y$
$\left(3\right) x < y$
$\left(4\right) y > x or y = x$
$\left(5\right) x = y$Or the relationship cannot be established.

I. $y - x = z$
II.$zx-1 = 0.0005$

In each of the question, two equations numbered I and II with variables $x$ and $y$ are  given. You have to solve both the equations to find the value of $x$ and $y$. Give answer:
A. If $x>y$
B. If $x\ge y$
C. If $x<y$
D. If $x\le y$
E. If $x=y$ or relationship between $x$ and $y$ can not be determined.

I. $28x^2-9x-9=0$
II. $7y^2+24y+9=0$

In each of the following questions two equations are given. You have to solve both the equation and find out the values of $x$ and $y$. And relation between them?

I. $4x^2 – 11x + 6 = 0$
II. $4y^2– 17y+18=0$

In following questions, two equations numbered I and II with variables$x$ and $y$ are given. You have to solve both the equations to find the relation between$x$ and $y$.

$$\begin{gathered} \mathrm{I})x^2-23x + 102 = 0 \\ \mathrm{II})y^2-35y + 306 = 0 \end{gathered}$$

In following questions, two equations numbered I and II with variables$x$ and $y$ are given. You have to solve both the equations to find the relation between$x$ and $y$.

$$\begin{gathered} \mathrm{I})2x^2 + 32x + 120 = 0 \\ \mathrm{II})y^2+ 16y + 48 = 0 \end{gathered}$$