Applications of Kohlrausch’s Law

IMPORTANT

Applications of Kohlrausch’s Law: Overview

This Topic covers sub-topics such as Kohlrausch's Law, Applications of Kohlrausch's Law, Molar Conductivity at Infinite Dilution and, Equivalent Conductivity at Infinite Dilution

Important Questions on Applications of Kohlrausch’s Law

EASY
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The law that states about independent migration of ions is:

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Find the solubility product of a saturated solution of Ag 2 CrO 4   at 298 K in water if the emf of the cell  Ag Ag + Ag 2 CrO 4 Ag + 0 .1 M Ag s is 0.164 V at 298 K.

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Electrolyte KCl KNO3 HCl NaOAc NaCl
 S cm2 mol-1 149.9 145.0 426.2 91.0 126.5


Calculate  Λ o HOAC  at infinite dilution in   H 2 O at   25°C :

MEDIUM
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The molar conductance at infinite dilution for sodium acetate, hydrochloric acid and sodium chloride are 91.0, 426.2 and 126.5 S cm2mol-1 respectively at 298 K. The molar conductance of acetic acid at infinite dilution would be

EASY
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The molar conductance and the specific conductance of an electrolyte are related by the formula

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The molar conductance of 0.01 M electrolyte is 124 ohm-1 cm2 mol-1 at 298 K. Calculate its specific conductance.

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The specific conductance of 0.01 M of an electrolyte is 1.24×10-3 ohm-1 cm-1 at 298 K. Calculate the molar conductance.

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Calculate the molar conductance of 0.02 M solution of an electrolyte which has a resistance of 310 ohm at 298 K. Cell constant is 0.68 cm-1.

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0.05 M NaOH offered a resistance of 31.2 ohm in a conductivity cell having a cell constant of 0.38 cm-1. Calculate the molar conductivity of NaOH solution.

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Calculate the molar conductance of 0.01 M solution of an electrolyte which has a resistance of 210 ohm at 298 K. Cell constant is 0.88 cm-1.

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Specific conductance of 0.1 M CH3COOH is 4.7×10-2 ohm-1 cm-1 at 298 K. Calculate its molar conductance.

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The equivalent conductivity of acetic acid at infinite dilution is 387 S cm2 eq-1. At the same temperature, for 0.001 M solution of acetic acid, it is 55 S cm2 eq-1. What is the degree of dissociation of 0.1 N acetic acid? Assume 1-α1

A : 1.5%B : 1.35%C : 2%

Enter your correct answer as A, B or C.

MEDIUM
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Which statement is not correct for Kohlrausch law?

HARD
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If the value of molar conductivities at infinite dilution for CH3COOHHCl and NaCl are 390.5, 425.4 and 126.4 S cm2mol-1 respectively at 298 K. Calculate the molar conductivity at infinite dilution of CH3COONa in S cm2mol-1. (Just mention the value, no requirement of units in the answer).

HARD
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The molar conductivity of a solution of a weak acid HX (0.01 M) is 10 times smaller than the molar conductivity of a solution of a weak acid HY (0.10 M). If λ°X-=λ°Y-, the difference in their pKa values, pKa(HX)-pKa(HY), is (consider degree of ionization of both acids to be <<1)

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Λ°m for NaCl, HCl and NaAc are 126.4, 425.9 and 91.0 S cm2 mol-1 respectively. Calculate Λ°m for HAc.

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The pH of a 0.1 molar solution of the acid HQ is 3 . The value of the ionisation constant, Ka of this acid is :

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The molar conductivities of KCl, NaCl and KNO3 at infinite dilution are 152, 128 and 111 Scm2 mol1 respectively. The molar conductivity of NaNO3 at infinite dilution is :-

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The specific conductance of AgCl solution in water was determined to be 1.8 × 106 Ω1 cm1 at 298K. The molar conductances at infinite dilution of Ag+Cl are 67.9 & 82.1 Ω-11cm2mol1. What is  the solubility of AgCl in water ?

HARD
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The maximum molar conductivities of X+3 and Y- ions are 200 and 100 S cm2 mol-1 respectively. The molar conductivity of XY3 at infinite dilution is :-