Mole Concept

The number of oxygen atoms in $4.4\mathrm{\hspace{0.17em}}\mathrm{g}$ of ${\mathrm{CO}}_2$ is:

The number of oxygen atoms in $4.4$ gram of $\text{C}{\text{O}}_2$ is
(Given that atomic mass $\text{C}$ and $\text{O}$ are $\text{12}$ and $\text{16}$ $\text{g/mol}$ )

The number of atoms in $0.1$ moles of a triatomic gas is:

 $({\mathrm{N}}_{\mathrm{A}}=6.023\times {10}^{23}\text{}{\mathrm{mol}}^{-1})$

$1\hspace{0.17em}\mathrm{cc} {\mathrm{N}}_2\mathrm{O}\mathrm{\hspace{0.17em}}\mathrm{at}\mathrm{\hspace{0.17em}}\mathrm{NTP}$ contains:

Which has maximum number of molecules?

If $N_A$ is Avogadro’s number then number of valence electrons in 4.2 g of nitride ions  $(N^{\mathrm{}3-})is$

1 gm of charcoal adsorbs 100 mL 0.5 M ${\mathrm{CH}}_3\mathrm{COOH}$ to form a monolayer, and thereby the molarity of ${\mathrm{CH}}_3\mathrm{COOH}$ reduces to 0.49. The surface area of the charcoal adsorbed by each molecule of acetic acid. $\left(\text{Surface area of charcoal = 3.01}\times {\text{10}}^2{\text{ m}}^2/\text{gm, Molarity}=\frac{\text{Number of moles}}{\text{1000 mL}}\right)$ will be:

How many moles of ${\mathrm{Al}}_2{\mathrm{O}}_3$will be formed when a mixture of $5.4 \mathrm{g} \mathrm{of} \mathrm{Al}$and $3.2 \mathrm{g} \mathrm{of} {\mathrm{O}}_2$ is heated?

Number of mole(s) of ${\mathrm{H}}_2{\mathrm{SO}}_4$ required to neutralise $20\mathrm{ml}, 1.5 \mathrm{N} \mathrm{NaOH}$ solution is

The number of nitrogen atoms present in $20$ litre of air containing $78\%$ nitrogen by volume at STP is

The number of molecules in $4.25 \mathrm{g}$ of ammonia is ?

Calculate weight of carbon in $39\mathrm{gm}$ of ${\mathrm{C}}_6{\mathrm{H}}_6$.

$1.2 \mathrm{g}$ of $\mathrm{P}$ is present in $2.2 \mathrm{g}$ of: