Zeros of a Polynomial

Find zero of following polynomial:

$x^2+\sqrt{5}$

What are zeroes of a polynomial?

Find the value of $p$ if $\left(x-p\right)$ is a factor of  $x^5-p^2{x}^3+2x+p+3$. Hence factorise $x^2+4px+3$.

Find the value of $a$ and $b$, if $x=2\text{ and }x=0$ are the zeroes of the polynomial $2x^3-5x^2+ax+b$.

Find the values of $p \text{and }q$:

 $5x^2+px+q= 0; x= -2, x= -\frac{1}{5}$

Find the value of $b$ so that $y+3$ is a factor of $y^2+by-5.$

If one zero of the quadratic polynomial $x^2+3x+k$ is $2$, then the value of $k$ is

If $\mathrm{P}\left(x\right)=4x^3+b{x}^2++cx+d, \mathrm{P}\left(1\right)=0, \mathrm{P}\left(2\right)=0, \mathrm{P}\left(3\right)=0$ then, find $\mathrm{P}\left(4\right)$.

Find the zeroes of $3x^2-29x+56=0$ by factorisation method.

Identify the zeroes of the given polynomial.

$p\left(z\right)=4z^2-15z\mathrm{\pi }-4{\mathrm{\pi }}^2$

Zero of the polynomial $\frac{-11x}{4}+1$

The number of zeroes of the polynomial $f\left(x\right)={\left(x-3\right)}^2+1$ is

If $\alpha , \beta$ are the zeros of the polynomial $f\left(x\right)=4x^2-4x+1$, find the value of $\frac{1}{{\alpha }^4}+\frac{1}{{\beta }^4}$.

Determine, if $3$ is root of the equation below:

$\sqrt{x^2-4x+3}+\sqrt{x^2-9}=\sqrt{4x^2-14x+16}$

Which of the following is the zero of $2\left(t+2008\right)\left(t-2009\right)\left(t+2010\right)$.

 If one zero of the quadratic polynomial $x^2 + 3x + k$ is $2$, then the value of $k$ is

A quadratic polynomial, whose zeroes are $–3$ and $4$, is

The zeroes of the quadratic polynomial $x^2 + 99x + 127$ are

If the discriminant of a quadratic polynomial, $D > 0$, then the polynomial has

If on division of a polynomial p(x) by a polynomial g(x), the quotient is zero, then the relation between the degrees of p(x) and g(x) is