Conversion of Galvanometer to Ammeter or Voltmeter

The reading on a high resistance voltmeter, when a cell is connected across it, is 2.5 V. When the terminals of the cell are also connected to resistance of  $5 \mathrm{\Omega }$  as shown in the circuit, the voltmeter reading drops to 2.0 V. The internal resistance of the cell is:

Two identical fuses are rated at $10A$

To convert a galvanometer into an ammeter, one should connect

What is the SI unit of the voltage sensitivity?

The SI unit of current sensitivity in galvanometer is

If an ammeter is to be used in place of a voltmeter, then with the ammeter we must connect a,

The ammeter has range of $1$ $\mathrm{A}$, without shunt. The range can be varied by using different shunt resistances. The graph between shunt resistance and range will have the nature as

A moving coil galvanometer of resistance $100 \mathrm{\Omega }$ is used as an ammeter using a resistance $0.1 \mathrm{\Omega }$. The maximum deflection current in the galvanometer is $100 \mathrm{\mu A}$. Find the minimum current in the circuit so that the ammeter shows maximum deflection.

A moving coil galvanometer of resistance $100 \mathrm{\Omega }$ is used as an ammeter using a resistance $0.1 \mathrm{\Omega }$. The maximum deflection current in the galvanometer is $100 \mathrm{\mu A}$. Find the minimum current in the circuit so that the ammeter shows maximum deflection.

A voltmeter has a $25 \mathrm{\Omega }$ coil and $575 \mathrm{\Omega }$ in series. The coil takes $10\mathrm{ }\mathrm{m}\mathrm{A}$ for full-scale deflection. The maximum potential difference which can be measured is -

In the given circuit, voltmeter reads $5 \mathrm{V}.$ The resistance of the voltmeter is:

What resistance should be connected in series of a galvanometer of resistance $R_g$ in order to change its range from $V$ volts to $N\mathrm{V}$ volts (in $\mathrm{ohm}$)

Three voltmeters all having different resistances are joined as shown. When some potential difference is applied across $P$ and $Q$, their readings are $V_1,V_2$ and $V_3$ respectively. Then

The resistance of an ammeter formed by converting a galvanometer will be:

Choose the incorrect statement-

Three voltmeters all having different resistances are joined as shown. When some potential difference is applied across $P$ and $Q$, their readings are $V_1,V_2$ and $V_3$ respectively. Then

A moving coil galvanometer is converted into an ammeter reading up to $0.03 \mathrm{A}$ by connecting a shunt of resistance $r/4.$ What is the maximum current which can be sent through this galvanometer, if no shunt is used. (Here $r=$ resistance of galvanometer) :-

A voltmeter has a $25 \mathrm{\Omega }$ coil and $575 \mathrm{\Omega }$ in series. The coil takes $10\mathrm{ }\mathrm{m}\mathrm{A}$ for full-scale deflection. The maximum potential difference which can be measured is