Peak and RMS Values of Alternating Current and Voltage

The instantaneous current and voltage of an AC circuit are given by $\mathrm{i}=10\sin \left(314\mathrm{t}\right) \mathrm{A}$ and $\mathrm{V}=100\sin \left(314\mathrm{t}\right) \mathrm{V}$. The power dissipation in the circuit is

An alternating voltage $E=200\sqrt{2}\sin \left(100\mathrm{t}\right)$ is connected to a $1$ micro farad capacitor through an AC ammeter. The reading of the ammeter shall be:

If a capacitor of $8\mathrm{ }\mathrm{\mu F}$ is connected to a $220\mathrm{ }\mathrm{V},\mathrm{ }100 \mathrm{H}\mathrm{z}$, AC source and the current passing through it is $65 \mathrm{m}\mathrm{A}$ then the rms voltage across it is

The peak voltage of an AC supply is $220 \mathrm{V}$, then its RMS voltage is

The relation between an $A.C.$ voltage source and time in $SI$ units is : $\mathrm{V}=240 \sin 100 \pi \mathrm{t} \cos 100 \pi \mathrm{t}$ volt, value of peak voltage and frequency will be respectively :-

The peak voltage of an AC supply is $440 \mathrm{V}$, then its RMS voltage is

If the peak voltage of a voltage supply is $4\sqrt{2} \mathrm{V}$, what is the RMS voltage of the supply?

A sinusoidal voltage of peak value $200$ volt is connected to a diode and resistor $R$ in the circuit shown so that half-wave rectification occurs. If the forward resistance of the diode is negligible compared to $R,$ the r.m.s. voltage across $R$ is approximately:

If the equation of alternating $\mathrm{emf}$ is $\mathrm{V}=200 \sin 300t$, then for a circuit containing $\mathrm{R}=100 \mathrm{\Omega }$ and $L=800 \mathrm{mH}$, the peak value of current will be in ampere :

An alternating voltage is given by :
$e=e_1 \sin \omega \mathrm{t}+e_2 \cos \omega \mathrm{t}$
Then the root mean square value of voltage is given by :

If a direct current of value $a$ ampere is superimposed on an alternating current $I=b\mathit{ }\sin \mathit{ }\omega t$ flowing through a wire, what is the effective value of the resulting current in the circuit?

A parallel plate capacitor (shown in figure) made of circular plates each of radius $R= 6.0 \mathrm{cm}$ has a capacitance $C=100 \mathrm{pF}$. The capacitor is connected to a $230 \mathrm{V}$ AC supply with angular frequency of $300 \mathrm{rad}/\mathrm{s}$.



What is the rms value of the conduction current?

For an $\mathrm{AC}$ given by $\mathrm{I}=50\cos \left(100\mathrm{t}+{45}^{\mathrm{o}}\right) \mathrm{A}$, the value of ${\mathrm{I}}_{\mathrm{rms}}=$ ______ $\text{A}$.

The peak voltage of an ac supply is $440 \mathrm{V}$, then its RMS voltage is

RMS value of alternating current is-

A certain alternating current when passed through a resistor produces heat which is thrice of that produced by a direct current of $2 \mathrm{A}$ in the same resistor. Calculate the RMS value of this alternating current.

What will be the reading of an AC ammeter if a square wave AC current of peak value $2 \mathrm{A}$ is passed through it?

The relation between an ac voltage source and time in $\mathrm{S}\mathrm{I}\mathrm{ }$ units is $V=120\sin \left(100\pi t\right)\cos \left(100\pi t\right)\mathrm{V}$ . What are the respective values of peak voltage and frequency ?

The peak voltage in a $220\mathrm{ }\mathrm{V}$ AC source is

Which of the following equations represents an alternating voltage in terms of peak voltage $V_m$?