Combination of Capacitors

The equivalent capacitance between the points $x$ and $y$ in the circuit shown is

Determine the equivalent capacitance of the combination shown In the following figure:

The resultant capacitance between points A and B in the given circuit is

In the following circuit, $C_1=12 \mathrm{\mu F}, C_2=C_3=4 \mathrm{\mu F}$ and $C_4=C_5=2 \mathrm{\mu F}$. The charge stored in $C_3$ is _____.

Find the charge on capacitor $C_3$?

Given that $C_1=C_2=C$ and $C_3=C_4=3C$

Find the equivalent capacitance between points $\mathrm{A}$ and $\mathrm{B}$ for the network shown in figure

For the network shown in figure, calculate equivalent capacitance between points $\mathrm{A}$ and $\mathrm{B}$

The equivalent capacitance of four identical capacitors, as shown in the figure is $15 \mathrm{\mu F}$. The value of each capacitor is

Calculate the equivalent capacitance between points A and B in the combination shown.

.

Three capacitors of capacitance $C\left(\mathrm{\mu }\mathrm{F}\right)$ are connected in parallel to which a capacitor of capacitance $C$ is connected in series. The effective capacitance is $3.75 \mathrm{\mu F}$, then the capacity of each capacitor is

Three capacitors $2 \mathrm{\mu F}, 3 \mathrm{\mu F}$ and $6 \mathrm{\mu }\mathrm{F}$ are joined with each other. What is the minimum effective capacitance (in $\mathrm{\mu F}$)?

Four plates of equal area $A$ are separated by equal distance $d$ and are arranged as shown in the figure. The equivalent capacity is:

Three capacitors each of $4\mathrm{ }\mathrm{\mu }\mathrm{F}$ are to be connected in such a way that the effective capacitance is $6\mathrm{ }\mathrm{\mu }\mathrm{F}$ . This can be done by connecting them:

A circuit has a section $AB$, shown in the figure. The emf of the source is equal to $10 \mathrm{V}$ and the capacitors capacitance are equal to $C_1=1.0 \mathrm{\mu F}$ and $C_2=2.0 \mathrm{\mu F}$. If the potential difference between points $A$ and $B$, ${\varphi }_{\mathrm{A}}-{\varphi }_{\mathrm{B}}=5.0 \mathrm{V},$ then the voltages $V_1$ and $V_2$ across each capacitors, $C_1$ and $C_2$, respectively, are

A network of four $20\mathrm{ }\mathrm{\mu }\mathrm{F}$ capacitors is connected to a $600 \mathrm{V}$ supply as shown in the figure.
Then, the equivalent capacitance of the network is $26.67 \mu \mathrm{F}$.

A parallel-plate capacitor consists of two identical metal plates. Two dielectric slabs having dielectric constants $K_1$ and $K_2$ are introduced in the space between two plates as shown below. Show that capacity of capacitor in the arrangement is given by $C=\frac{{\epsilon }_0\left(K_1+K_2\right)A}{2d}$

A network of four capacitors $5 \mathrm{\mu F}$ each are connected to a $240 \mathrm{V}$ supply. Determine the charge on each capacitor.

Derive an expression for effective capacitance of three capacitors connected in parallel.

What is the equivalent capacitance of two $2 \mathrm{\mu F}$ capacitors connected in series.

How will you obtain a capacitance of higher value if you have been provided with capacitors of relatively low capacitance?