Coulomb's Law

$\sqrt{3}\times {10}^{-19} \mathrm{C}$ and $-{10}^{-6} \mathrm{C}$ are placed at $\left(0,0,0\right)$ and $\left(1,1,1\right)$ respectively. The force on the second is of the form

Two point charges $+4\mu \mathrm{C}$ and $+2\mu \mathrm{C}$ repel each other with a force of $8 \mathrm{N}$. If a charge $-4 \mathrm{\mu C}$ is added to each of these charges, the force would be:

The centres of two identical small conducting spheres are $1 \mathrm{m}$ apart. They carry charges of opposite kind and attract each other with a force $F$. When they are connected by a conducting thin wire they repel each other with a force $\frac{F}{3}.$ What is the ratio of the magnitude of charges carried by the spheres initially?

A charge $Q$ is placed at each of the two opposite corners of a square. A charge $q$ is placed at each of the other two corners. If the resultant force on $Q$ is zero, then

Electric charges of $1 \mathrm{\mu C},-1 \mathrm{\mu C}$ and $2 \mathrm{\mu C}$ are placed in air at the corners $A,B$ and $C$ respectively of an equilateral triangle $ABC$ having length of each side $10 \mathrm{cm}.$ The resultant force on the charge at $C$ is

Two conducting spheres of radii $3 \mathrm{cm}$ and $1 \mathrm{cm}$ are separated by a distance of $10 \mathrm{cm}$ in free space. If the spheres are charged to same potential of $10 \mathrm{V}$ each, the force of  repulsion between them is

A charged ball $B$ hangs from a silk thread $S,$ which makes an angle $\theta$ with a large charged conducting sheet $P,$ as shown in the figure. The surface charge density $\sigma$ of the sheet is proportional to

A charge $Q_1$ exerts force on a second charge $Q_2.$ If a third charge $Q_3$ is brought near, the force of $Q_1$ exerted on $Q_2$

 As per Coulomb's law, the force of attraction or repulsion between two point charges is directly proportional to the

The electrostatic force acting on a charge q lying at a distance of $2 \mathrm{cm}$ on axial position from centre of a dipole is $64 \mathrm{N},$ now if this distance is made double, then find the new value of force. Assume that separation between two charge of the dipole is less than $4 \mathrm{cm}$

The ratio of $q$ and $Q$ so as to make the system in equilibrium is :

Two point charges are kept in air with a separation between them. The force between them is $F_1$, if half of the space between the charges is filled with a dielectric of dielectric constant $4$ and the force between them is $F_2$, if ${\left(\frac{1}{3}\right)}^{\mathrm{rd}}$ of the space between the charges is filled with dielectric of dielectric constant$9$. Then $\frac{F_1}{ F_2}$ is

When distance between two-point charges is increased by $10\%$, the force of interaction

A charge $q$ is placed at the centre of the line joining two equal charges $Q .$ The system of the three charges will be in equilibrium if $\mathrm{q}$ is equal to

Below the fixed end of the insulating horizontal thread, at a distance equal to the length $\left(l=10 \mathrm{cm}\right)$ of the thread, there is a fixed charge which has the same charge as the charge $\left(Q=1 \mathrm{\mu C}\right)$ of the small body of mass $m$ at the end of the thread as shown in the figure.
The body is released. When it is at the lowest position the angle between the thread and the horizontal is $30°$. The mass of the moving body is closest to:

In the figure shown, $A$ is a fixed charge and $B$ (of mass $m$) is given a velocity $v$ perpendicular to line $AB.$ At this moment, the radius of curvature of the resultant path of $B$ is

The force between two small charged spheres having charges of $1\times {10}^{-7} \mathrm{C}$ and $2\times {10}^{-7} \mathrm{C}$ placed $20 \mathrm{cm}$ apart in air is _____.

Two point charges A and B, having charges $+\mathrm{Q}$ and $-\mathrm{Q}$ respectively, are placed at certain distance apart and force acting between them is $\mathrm{F}$. If  $25\mathrm{\%}$ charge of A is transferred to B, then the force between the charges becomes