Cyclotron

A particle of mass $2\times {10}^{-3} \mathrm{kg}$, charge $4\times {10}^{-3} \mathrm{C}$ enters in an electric field of  $5 \mathrm{V} {\mathrm{m}}^{-1}$, then its kinetic energy after$10 \mathrm{s}$ is

Singly charged ions ${\mathrm{He}}^{+}$ are accelerated in a cyclotron so that their maximum orbital radius is $r=60\mathrm{cm}$. The frequency of a cyclotron's oscillator is equal to $v=10.0\mathrm{MHz}$, the effective accelerating voltage across the dees is $V=50\mathrm{kV}$. Neglecting the gap between the dees, find:

(a) the total time of acceleration of the ion;
(b) the approximate distance covered by the ion in the process of its acceleration

A cyclotron of radius $36 \mathrm{m}$ is used to accelerate protons to a kinetic energy of $1 \mathrm{MeV}$ using a magnetic field of $4 \mathrm{T}.$ What should be the radius of the cyclotron if it is desired to use the same field strength to accelerate protons to $4 \mathrm{MeV}?$

What is the cyclotron give its construction and working?

What is the working principle of a cyclotron?

Which of the following cannot be accelerated in a cyclotron?

A proton, a deuteron and an alpha particle having the same kinetic energy are moving in circular trajectories in a constant magnetic field. If ${\mathrm{r}}_{\mathrm{P}}, {\mathrm{r}}_{\mathrm{d}} \mathrm{and} {\mathrm{r}}_{\mathrm{\alpha }}$ denote respectively the radii of trajectories of these particles, then

An electron moves with a velocity of $2\times {10}^5 \raisebox{1ex}{$\mathrm{m}$}\!\left/ \!\raisebox{-1ex}{$\sec $}\right.$ along the $-\mathrm{ve}$ direction of $\mathrm{x}-\mathrm{axis}$ in a magnetic field $\overrightarrow{\mathrm{B}}=\left(\hat{\mathrm{i}}-4\hat{\mathrm{j}}-3\hat{\mathrm{k}}\right)\mathrm{T}$. The magnetic of the force (in Newton) experienced by the electron is-

An electron beam passes through a magnetic field of $2\times {10}^{-3} \raisebox{1ex}{$\mathrm{Wb}$}\!\left/ \!\raisebox{-1ex}{${\mathrm{m}}^2$}\right.$ and an electric field of $1.0\times {10}^4 \raisebox{1ex}{$\mathrm{V}$}\!\left/ \!\raisebox{-1ex}{$\mathrm{m}$}\right.$ both acting simultaneously. The path of electron remain undeviating. The speed of electron if the electric field is removed and the radius of electron path will be respectively.

A beam of electron passes undeviated through mutually ${\perp }^{\mathrm{r}} \overrightarrow{\mathrm{E}}$ and $\overrightarrow{\mathrm{B}}$ of respective strength $\mathrm{E}=7.2\times {10}^6 {\mathrm{NC}}^{-1}, \mathrm{B}=2.4\mathrm{T}$ the velocity of the electron is

In cyclotron, radius of circular path traced by positive ions is_____

A Cyclotron is used to accelerate _____

Describe construction of Cyclotron.

Cyclotron does not accelerate electron because mass of the electron is very small.

Assertion: Cyclotron is an accelerating device.

Reason: Neutrons can be accelerated by the cyclotron.

A cyclotron's oscillator frequency is $10\mathrm{MHz}$. What should be the operating magnetic field for accelerating protons? (mass of the proton $=1.67\times {10}^{-27} \mathrm{kg}$ )

A cyclotron's oscillator frequency is $10 \mathrm{MHz}$ and the operating magnetic field is $0.66 \mathrm{T}$. If the radius of its dees is $60 \mathrm{cm}$, then the kinetic energy of the proton beam produced by the accelerator is

Calculate the magnetic field in which the cyclotron dees should be placed to accelerate protons. The applied frequency is $8$ megacycles/second. Take proton mass $1.67 \mathrm{x} {10}^{-27} \mathrm{kg}.$

A cyclotron provides maximum kinetic energy $2 \mathrm{MeV}$ to a deuteron. Find maximum kinetic energy given to a particle.

A cyclotron is operating at a frequency of $12 \mathrm{MHz}$. Mass and charge of deuteron are $3.3\times {10}^{-27} \mathrm{kg}$ and $1.6\times {10}^{-19} \mathrm{C}$. To accelerate deutron, the necessary magnetic field is