If the potential of $A$ is $10 \mathrm{V},$ then potential of $B$ is:

Capacitance, $C_1= 2C_2 = 2C_3$ and, the potential difference across, $C_1, C_2$ and $C_3$ are $V_1, V_2$ and $V_3$ respectively then:

In the circuit shown in the figure, the battery is an ideal one with emf $V$. The capacitor is initially uncharged. Switch, $S$ is closed at time $t=0$.

The final charge $Q$ on the capacitor is:

In the circuit shown in the figure, the battery is an ideal one with E.M.F. $V$. The capacitor is initially uncharged. Switch, $S$ is closed at time $t=0$.

The final charge, $Q$ on the capacitor, is, what is the current in the steady-state is?

A light bulb, a capacitor, and a battery are connected together as shown here, with the switch $S$ initially open. When the switch $S$ is closed, which one of the following is true?

The capacity of a parallel plate air capacitor is $10 \mathrm{\mu F}$. As shown in the figure, this capacitor is divided into two equal parts. These parts are filled by media of dielectric constants $K_1=2$ and $K_2=4.$ The capacity of this arrangement will be

Three capacitors, each of value, $1 \mu \mathrm{F}$ are so combined that the resultant capacity is $1.5 \mu \mathrm{F}$. Then:

A capacitor is charged with a battery and energy stored is $\mathrm{U}$. After disconnecting the battery another capacitor of same capacity is connected in parallel with it. The energy stored in each capacitor is:

Three capacitors of capacitances, $3 \mu \mathrm{F}, 10 \mu \mathrm{F}$ and $15 \mu \mathrm{F}$are connected in series to a voltage source of, $100 \mathrm{V}$. The charge on $15 \mu \mathrm{F}$ is: