The lengths, in centimeters, of some horned vipers are recorded in the table. Length Frequency Class width Frequency density 45 ≤ x < 55 13 10 1 . 3 55 ≤ x < 60 20 60 ≤ x < 65 26 65 ≤ x < 72 19 Copy and complete the table.

Class width of a class interval is difference between upper and lower boundaries of that class. Frequency density of class interval = Frequency class width for class interval 55 ≤ x < 60 , class width = 60 - 55 = 5 , frequency density = 20 5 = 4 for class interval 60 ≤ x < 65 , class width = 65 - 60 = 5 , frequency density = 26 5 = 5 . 2 for class interval 65 ≤ x < 72 , class width = 72 - 65 = 7 , frequency density = 19 7 = 2 . 71 So, the given table is Length Frequency Class width Frequency density 45 ≤ x < 55 13 10 1 . 3 55 ≤ x < 60 20 5 4 60 ≤ x < 65 26 5 5 . 2 65 ≤ x < 72 19 7 2 . 71

The lengths, in centimeters, of some horned vipers are recorded in the table. Length Frequency Class width Frequency density 45 ≤ x < 55 13 10 1 . 3 55 ≤ x < 60 20 60 ≤ x < 65 26 65 ≤ x < 72 19 Construct a frequency density histogram for this data.

Class width of a class interval is difference between upper and lower boundaries of that class. Frequency density of class interval = Frequency class width for class interval 55 ≤ x < 60 , class width = 60 - 55 = 5 , frequency density = 20 5 = 4 for class interval 60 ≤ x < 65 , class width = 65 - 60 = 5 , frequency density = 26 5 = 5 . 2 for class interval 65 ≤ x < 72 , class width = 72 - 65 = 7 , frequency density = 19 7 = 2 . 71 So, the given table is Length Frequency Class width Frequency density 45 ≤ x < 55 13 10 1 . 3 55 ≤ x < 60 20 5 4 60 ≤ x < 65 26 5 5 . 2 65 ≤ x < 72 19 7 2 . 71 Now frequency density histogram is constructed by plotting length on x - axis and frequency density on y - axis. Draw the bars with no gaps between them. The frequency density histogram is as follows

The ages of people visiting the Eiffel Tower are recorded in the table. Age, x (years) Frequency 0 < x ≤ 15 15 15 < x ≤ 25 28 25 ≤ x < 40 30 40 ≤ x < 60 42 60 ≤ x < 100 20 Construct a frequency density histogram for this data.

Given data is ages of people visiting the tower Class width of a class interval is difference between upper and lower boundaries of that class. Frequency density of class interval = Frequency class width So, the given table is Age, x (years) Frequency Class width Frequency density 0 < x ≤ 15 15 15 - 0 = 15 15 15 = 1 15 < x ≤ 25 28 25 - 15 = 10 28 10 = 2 . 8 25 ≤ x < 40 30 40 - 25 = 15 30 15 = 2 40 ≤ x < 60 42 60 - 40 = 20 42 20 = 2 . 1 60 ≤ x < 100 20 100 - 60 = 40 20 40 = 0 . 5 Now frequency density histogram is constructed by plotting age on x - axis and frequency density on y - axis. Draw the bars with no gaps between them. The frequency density histogram is as follows

The ages of people visiting the Eiffel Tower are recorded in the table. Age, x (years) Frequency 0 < x ≤ 15 15 15 < x ≤ 25 28 25 ≤ x < 40 30 40 ≤ x < 60 42 60 ≤ x < 100 20 State the modal class for this data.

Given data is ages of people visiting the tower Class width of a class interval is difference between upper and lower boundaries of that class. Frequency density of class interval = Frequency class width So, the given table is Age, x (years) Frequency Class width Frequency density 0 < x ≤ 15 15 15 - 0 = 15 15 15 = 1 15 < x ≤ 25 28 25 - 15 = 10 28 10 = 2 . 8 25 ≤ x < 40 30 40 - 25 = 15 30 15 = 2 40 ≤ x < 60 42 60 - 40 = 20 42 20 = 2 . 1 60 ≤ x < 100 20 100 - 60 = 40 20 40 = 0 . 5 The modal class of data with varying widths is the class interval with highest frequency density. So, 15 < x ≤ 25 is modal class as it has frequency density of value 2 . 8 .

The doctors at a medical center see 80 patients in total during morning surgery. The table gives information about the lengths of these appointments in minutes. Length, L (min) Frequency 0 < L ≤ 5 7 5 < L ≤ 7 15 7 < L ≤ 9 24 9 < L ≤ 13 19 13 < L ≤ 16 9 16 < L ≤ 20 6 Construct a frequency density histogram for the information.

Given data is length of appointment times taken by patients Class width of a class interval is difference between upper and lower boundaries of that class. Frequency density of class interval = Frequency class width So, the given table is Length, L (min) Frequency Class width Frequency density 0 < L ≤ 5 7 5 - 0 = 5 7 5 = 1 . 4 5 < L ≤ 7 15 7 - 5 = 2 15 2 = 7 . 5 7 < L ≤ 9 24 9 - 7 = 2 24 2 = 12 9 < L ≤ 13 19 4 19 4 = 4 . 75 13 < L ≤ 16 9 3 9 3 = 3 16 < L ≤ 20 6 4 6 4 = 1 . 5 Now frequency density histogram is constructed by plotting appointment length on x - axis and frequency density on y - axis. Draw the bars with no gaps between them. The frequency density histogram is as follows

EASY

MYP:4-5

IMPORTANT

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The histogram shows the relative frequency of items sold at different prices at a community fundraising event. There were $32$ items in total.

Calculate how many items sold for less than $16$ dollars.

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Important Questions on City Skylines (Histograms)

EASY

MYP:4-5

IMPORTANT

MYP Mathematics A concept based approach 4&5 Standard>Chapter 11 - City Skylines (Histograms)>Practice 5>Q 1

The lengths, in centimeters, of some horned vipers are recorded in the table.

Length	Frequency	Class width	Frequency density
$45 \leq x < 55$	$13$	$10$	$1.3$
$55 \leq x < 60$	$20$
$60 \leq x < 65$	$26$
$65 \leq x < 72$	$19$

Copy and complete the table.

MEDIUM

MYP:4-5

IMPORTANT

MYP Mathematics A concept based approach 4&5 Standard>Chapter 11 - City Skylines (Histograms)>Practice 5>Q 1

The lengths, in centimeters, of some horned vipers are recorded in the table.

Length	Frequency	Class width	Frequency density
$45 \leq x < 55$	$13$	$10$	$1.3$
$55 \leq x < 60$	$20$
$60 \leq x < 65$	$26$
$65 \leq x < 72$	$19$

Construct a frequency density histogram for this data.

MEDIUM

MYP:4-5

IMPORTANT

MYP Mathematics A concept based approach 4&5 Standard>Chapter 11 - City Skylines (Histograms)>Practice 5>Q 2

The ages of people visiting the Eiffel Tower are recorded in the table.

Age, $x$ (years)	Frequency
$0 < x \leq 15$	$15$
$15 < x \leq 25$	$28$
$25 \leq x < 40$	$30$
$40 \leq x < 60$	$42$
$60 \leq x < 100$	$20$

Construct a frequency density histogram for this data.

MEDIUM

MYP:4-5

IMPORTANT

MYP Mathematics A concept based approach 4&5 Standard>Chapter 11 - City Skylines (Histograms)>Practice 5>Q 2

The ages of people visiting the Eiffel Tower are recorded in the table.

Age, $x$ (years)	Frequency
$0 < x \leq 15$	$15$
$15 < x \leq 25$	$28$
$25 \leq x < 40$	$30$
$40 \leq x < 60$	$42$
$60 \leq x < 100$	$20$

Construct a frequency density histogram for this data. From the graph, Voleta estimates that there were ten visitors between $60$ and $80$ years old, and ten visitors between $80$ and $100$ years old. Explain the assumption Voleta has made.

MEDIUM

MYP:4-5

IMPORTANT

MYP Mathematics A concept based approach 4&5 Standard>Chapter 11 - City Skylines (Histograms)>Practice 5>Q 2

The ages of people visiting the Eiffel Tower are recorded in the table.

Age, $x$ (years)	Frequency
$0 < x \leq 15$	$15$
$15 < x \leq 25$	$28$
$25 \leq x < 40$	$30$
$40 \leq x < 60$	$42$
$60 \leq x < 100$	$20$

State whether you think this is a reasonable assumption. Justify your answer.

EASY

MYP:4-5

IMPORTANT

MYP Mathematics A concept based approach 4&5 Standard>Chapter 11 - City Skylines (Histograms)>Practice 5>Q 2

The ages of people visiting the Eiffel Tower are recorded in the table.

Age, $x$ (years)	Frequency
$0 < x \leq 15$	$15$
$15 < x \leq 25$	$28$
$25 \leq x < 40$	$30$
$40 \leq x < 60$	$42$
$60 \leq x < 100$	$20$

State the modal class for this data.

MEDIUM

MYP:4-5

IMPORTANT

MYP Mathematics A concept based approach 4&5 Standard>Chapter 11 - City Skylines (Histograms)>Practice 5>Q 3

The doctors at a medical center see $80$ patients in total during morning surgery. The table gives information about the lengths of these appointments in minutes.

Length, $L$ (min)	Frequency
$0 < L \leq 5$	$7$
$5 < L \leq 7$	$15$
$7 < L \leq 9$	$24$
$9 < L \leq 13$	$19$
$13 < L \leq 16$	$9$
$16 < L \leq 20$	$6$

Construct a frequency density histogram for the information.

MEDIUM

MYP:4-5

IMPORTANT

MYP Mathematics A concept based approach 4&5 Standard>Chapter 11 - City Skylines (Histograms)>Practice 5>Q 3

The doctors at a medical center see $80$ patients in total during morning surgery. The table gives information about the lengths of these appointments in minutes.

Length, $L$ (min)	Frequency
$0 < L \leq 5$	$7$
$5 < L \leq 7$	$15$
$7 < L \leq 9$	$24$
$9 < L \leq 13$	$19$
$13 < L \leq 16$	$9$
$16 < L \leq 20$	$6$

Calculate an estimate for the number of patients who saw their doctor for between $10$ and $15$ minutes.

Number of patients should be a integer without any decimal places, so round it off to zero decimal places.

The histogram shows the relative frequency of items sold at different prices at a community fundraising event. There were 32 items in total. Calculate how many items sold for less than 16 dollars.

Important Questions on City Skylines (Histograms)

Learn and Prepare for any exam you want !

The histogram shows the relative frequency of items sold at different prices at a community fundraising event. There were $32$ items in total.

Calculate how many items sold for less than $16$ dollars.